Both of them can have a low or a high energy.
The question is essentially meaningless for the above reason, but let's try to answer it anyway.
Neutrons have an inherent energy equivalent to their mass (which is, for a subatomic particle, pretty substantial).
The energy of a photon can be pretty much any desired value. Low-energy photons have low frequencies; high-energy photons have high frequencies.
The energy equivalent of a neutron at rest is roughly equal to that of a photon with a frequency of 2.2 x 1023 Hz. This is an amazingly high frequency (way up in the gamma region of the spectrum, which starts at around 1019Hz), so it's rather likely that for any given photon/neutron pair, the neutron has a higher overall energy.
Gamma-ray bursts can contain photons with energies far higher than a neutron at rest, though. The neutron energy is around a GeV; gamma-ray bursts can have photons with energies in excess of 10 TeV, 10,000 times higher.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
energy of one packet of light
All particles which represents a quantum of light and other electromagnetic radiation is called photon. The photons with the highest energies are gamma or X-rays, UV light, Blue light, and radio waves.
A photon of this wavelength has an energy of about 10 ^ -5 eV.
Packet of energy refers to a quantized or definite amount of energy carried by a particle. This packet energy or lumps of energy depends on the wavelength which can be found from Planck's formula E=hf. This is the idea originally provided by Max Planck to explain Black Body Radiation and to solve Ultra-violate catastrophe which later on came out to be the inception of Quantum Mechanics.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
energy of one packet of light
All particles which represents a quantum of light and other electromagnetic radiation is called photon. The photons with the highest energies are gamma or X-rays, UV light, Blue light, and radio waves.
A photon of this wavelength has an energy of about 10 ^ -5 eV.
A Photon does not have any mass. It is merely a packet of energy. To calculate the energy of a photon, the formula is E = hνwhere h = Planck's constant = 6.63 x 10-34and ν = frequency of the light source (in Hz)
Only one photon is produced per electron in any de-excitation. The number of energy levels it drops only determines the energy of the photon emitted.
Packet of energy refers to a quantized or definite amount of energy carried by a particle. This packet energy or lumps of energy depends on the wavelength which can be found from Planck's formula E=hf. This is the idea originally provided by Max Planck to explain Black Body Radiation and to solve Ultra-violate catastrophe which later on came out to be the inception of Quantum Mechanics.
If the color (frequency, wavelength) of each is the same, then each photon carries the same amount of energy. Three of them carry three times the energy that one of them carries.
Depending on the energy (frequency) of the specific photon hitting the electron, one of three events happens: nothing, the electron is excited, or the electron leaves the atom. If the energy of the photon very high, the electron can absorb the energy and escape the nucleus' pull. This is called ionization. If the energy of the photon lines up with the energy spacing in the atoms energy levels, the electron will move to a higher energy state, becoming excited. The electron then returns to its original energy level, releasing the energy as light. If the energy of the photon does not fall into one of these categories, the electron does not interact with it. In terms of actually changing the electron, it only changes in energy, not any other property.
Photon energy can be increased by following two methods. 1). by increase in frequency of one photon as (E = hf); where f denotes the frequency of corresponding region. In this case, the electromagnetic region will change to higher frequency region or shorter wavelength region. The photon energy may increase, but not the intensity. 2). secondly increase in the number of photons (n) as E= nhf. If the number of photons of a particular frequency increase, photon energy also increases. In this case, intensity of light of definite frequency (either blue, red etc.) increase simultaneously.
The electron falling one or more energy shells will produce a photon of energy equal to the difference in energy actually two or more in different directions all adding to the energy
neutron