Both of them can have a low or a high energy.
The question is essentially meaningless for the above reason, but let's try to answer it anyway.
Neutrons have an inherent energy equivalent to their mass (which is, for a subatomic particle, pretty substantial).
The energy of a photon can be pretty much any desired value. Low-energy photons have low frequencies; high-energy photons have high frequencies.
The energy equivalent of a neutron at rest is roughly equal to that of a photon with a frequency of 2.2 x 1023 Hz. This is an amazingly high frequency (way up in the gamma region of the spectrum, which starts at around 1019Hz), so it's rather likely that for any given photon/neutron pair, the neutron has a higher overall energy.
Gamma-ray bursts can contain photons with energies far higher than a neutron at rest, though. The neutron energy is around a GeV; gamma-ray bursts can have photons with energies in excess of 10 TeV, 10,000 times higher.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
No, the energy of a photon is directly related to its frequency, not its period. Photons with the highest energy have the shortest wavelength and the highest frequency. Period is the time taken to complete one full cycle of a wave, and it is inversely related to frequency.
The energy of one photon in yellow light depends on the specific shade of yellow, as it corresponds to a range of wavelengths. Generally, for yellow light with a wavelength around 580 nanometers, the energy of one photon is approximately 2.14 electronvolts.
The energy of one photon is directly proportional to its frequency. This relationship is described by Planck's equation: E hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon. The behavior of light, including its interactions with matter and its wave-particle duality, is influenced by the energy of its constituent photons.
All particles which represents a quantum of light and other electromagnetic radiation is called photon. The photons with the highest energies are gamma or X-rays, UV light, Blue light, and radio waves.
No, it could not. A blue photon carries more energy than a red photon, since the blue photon's frequency is higher. That means one red photon wouldn't deliver enough energy to the atom to give it the energy to emit a blue photon.
No, the energy of a photon is directly related to its frequency, not its period. Photons with the highest energy have the shortest wavelength and the highest frequency. Period is the time taken to complete one full cycle of a wave, and it is inversely related to frequency.
The energy of one photon in yellow light depends on the specific shade of yellow, as it corresponds to a range of wavelengths. Generally, for yellow light with a wavelength around 580 nanometers, the energy of one photon is approximately 2.14 electronvolts.
The energy of one photon is directly proportional to its frequency. This relationship is described by Planck's equation: E hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon. The behavior of light, including its interactions with matter and its wave-particle duality, is influenced by the energy of its constituent photons.
All particles which represents a quantum of light and other electromagnetic radiation is called photon. The photons with the highest energies are gamma or X-rays, UV light, Blue light, and radio waves.
The total energy of a photon with a wavelength of 3000 A is divided into two photons, one red photon with a wavelength of 7600 A, and another photon with a shorter wavelength. To calculate the wavelength of the second photon, you can use the conservation of energy principle, where the sum of the energies of the two new photons is equal to the energy of the original photon. This will give you the wavelength of the other photon.
The energy of a photon can be calculated using the equation E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Plugging in the values for h, c, and λ, we can calculate the energy of one photon at 400 nm. To find the energy of 1 mol of photons, we would multiply the energy of one photon by Avogadro's number.
A Photon does not have any mass. It is merely a packet of energy. To calculate the energy of a photon, the formula is E = hνwhere h = Planck's constant = 6.63 x 10-34and ν = frequency of the light source (in Hz)
The energy of one photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J·s) and f is the frequency of the photon. For example, a photon of green light with a frequency of around 5.5 x 10^14 Hz has an energy of about 3.66 x 10^-19 Joules.
If the color (frequency, wavelength) of each is the same, then each photon carries the same amount of energy. Three of them carry three times the energy that one of them carries.
The distance between the crest of one photon wave and the next is called the wavelength. It is a measure of the spatial extent of the wave and determines the color and energy of the photon.
A photon is a packet of energy that carries a quantum of energy. It is an elementary particle that is the quantum of the electromagnetic field, including electromagnetic radiation such as light. The energy of a photon is directly proportional to its frequency and inversely proportional to its wavelength.