(n + 6) - 5 which can be simplified to n + 1
Incidentally, the word is subtracted.
Find the sum of the first hundred even natural number divisible by 5?
5
5 5+4 = 9 52+42 = 41
the quotient of 12 and a number h
First write down '5 + b' NB in algebra you must always show the plus sign. Next put the '5 + b' in brackets. ; (5 + b) When you require half of this value , you are dividing by '2' . So it is written as (5 + b)/2 NNB the 'slash sign ; '/' represents divide in algebra. NNNB Do not write 5 + b/2 , because this means the 'whole number '5' is added to half of 'b' only/ You must use the brackets. e.g. Let 'b' = 7 So '5 + 7' = ( 5 + 7) => ( 5 + 7) / 2 #Remember the rule in maths ; you do inside the brackets first. Hence ( 5 + 7) / 2 = 12 /2 Then divide 12/2 = 6 The Answer. For the other method you will a completely different answer. 5 + 7/2 = 5 + 3.5 = 8.5 Hope that helps!!!!!
Once.
5
" 3x + 5 " does.
10 < x + 5 < 20
The algebraic expression for "4 less than the sum of a number and 5" is (n + 5) - 4, where n represents the unknown number.
3, 5, 7 and 9.
3*(5+x) or 3(5+x)
The sum of 3 and a number, equaling 5, (if you want to know what the number is...) is 2 3+2=5
In Roman numerals, the symbol "V" represents the number 5.
And the sum of 5..? Uhh... Is it 5?
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
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