H2SO4(aq)
i donβt knwo
Hydrogen
There will be no reaction between the lithium and the potassium hydroxide. However, since the potassium hydroxide is in solution, the lithium will still react with the water to form lithium hydroxide and hydrogen gas. 2Li + H2O --> H2 + LiOH.
Acid: HNO3 (Nitric Acid) Base: LiOH (Lithium Hydroxide) HNO3 + LiOH --> LiNO3 + H2O
The balanced reaction of LiOH + CO2 to produce Li2CO3 + H2O is as follows. 2 LiOH + CO2 --> Li2CO3 + H2O.
This equation is:HBr + LiOH = LiBr + H2O
Li does NOT react slowly with water. It reacts vigorously to produce LiOH + H2 gas.
HCI
Hydrogen
There will be no reaction between the lithium and the potassium hydroxide. However, since the potassium hydroxide is in solution, the lithium will still react with the water to form lithium hydroxide and hydrogen gas. 2Li + H2O --> H2 + LiOH.
2 LiOH + CO2 = H2O + Li2CO3
Assuming that "lituam" was intended to read "lithium", the equation is: 2 Li + 2 H2O -> 2 LiOH + H2.
HCl + LiOH ----> LiCl + H2O
Acid: HNO3 (Nitric Acid) Base: LiOH (Lithium Hydroxide) HNO3 + LiOH --> LiNO3 + H2O
Balanced equation: LiOH + HBr ---> LiBr + H₂O Here, we aim to convert the mass of LiOH to mass of LiBr. In this formula, the product (LiBr) takes x, and the reactant (LiOH) takes y. Here's how it goes. (? = coefficient in the balanced equation) mass of x = (mole of y) * (? mol x / ? mol y) * (molar mass of x) mass of LiBr = (10 g / 23.95 g/mol) * (1 mol LiBr / 1 mol LiOH) * (86.85 g/mol LiBr) mass of LiBr = 36.3 g (Answer)
Bases, for example NaOH, KOH, LiOH, etc.
LiOH
Lithium hydroxide disassociates completely in solution which is the definition of a strong acid.