The ion MnO4 is reduced toMnO2 and sulfur is oxidized to ion sulfate. Sulfite is the reducing agent.
Na
Na2SO3
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This reaction is the following:2 KMnO4 + SO2 = 2 MnO2 + K2SO4
KMnO4 and glycerine undergo a vigorous oxidation/reduction reaction. KMnO4 is a very strong oxidizing agent, and when in contact with alcohols or poly hydroxy compounds, there is a strong reaction. With glycerol, it is 3 C3H5(OH)3 + 14 KMnO4 --> 14 MnO2 + 7 K2CO3 + 2 CO2 + 12 H2O.So, it is basically a combustion reaction of an organic triol, resulting in CO2 and H2O, and MnO2 as the reduced form of MnO4.
As we all know that the potassium permanganate (KMnO4) is the dark purple color solution ...and in titration it become colorless ....so when the titration is completed ...and the other single drop of KMnO4 solution produce pinkish colour in a beaker ...which indicate that the reaction was completed just a single drop before .. we use indicator in a a reaction in order to indicate ...but we dont used indicator in titration with KMnO4 because it also indicate us by changing its color ...colorless to pink
acidicness number of kmno4
as kmno4 acts as a strong reducing agent only in acid medium
KMnO4 + C3H8O3 => K2CO3 + H2O + CO2 + MnO2
The reaction is:CH3-CH=CH2 + KMnO4 ------> CH3-COOH + CO2 + H2O
no reaction equation
MnCl2: oxidation number +2MnO2: oxidation number +4KMnO4: oxidation number +7
no reaction takes place
KMnO4 will oxidize the HCl to Cl2 gas, a potentially hazardous vapor.
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This reaction is the following:2 KMnO4 + SO2 = 2 MnO2 + K2SO4
one such reaction is glycerine plus KMno4
The formula for potassium permanganate is KMnO4
KMnO4 and glycerine undergo a vigorous oxidation/reduction reaction. KMnO4 is a very strong oxidizing agent, and when in contact with alcohols or poly hydroxy compounds, there is a strong reaction. With glycerol, it is 3 C3H5(OH)3 + 14 KMnO4 --> 14 MnO2 + 7 K2CO3 + 2 CO2 + 12 H2O.So, it is basically a combustion reaction of an organic triol, resulting in CO2 and H2O, and MnO2 as the reduced form of MnO4.