Which type o lines match these equations x 2y plus 6 4y 2x-12?
Without any equality signs the given terms can't be considered to be equations.
The two equations represent the same straight line.
When will be the linear equations a1x plus b1y plus c1 equals 0 and a2x plus b2y plus c2 equals 0 has unique solution?
When (the graph of the equations) the two lines intersect. The equations will tell you what the slopes of the lines are, just look at them. If they are different, then the equations have a unique solution..
If you mean: x+y = 10 and x-y = 6 then y = -x+10 and y = x+6 which means the lines are perpendicular to each other
Those two statements are linear equations, not lines. If the equations are graphed, each one produces a straight line. The lines intersect at the point (-1, -2).
The lines are parallel.
They are parallel.
There are two equations in the question, not one. They are the equations of intersected lines, and their point of intersection is their common solution.
None. When these two equations are graphed, the two lines are parallel. Since they never intersect, there is no point that satisfies both equations.
None. The lines described by the two equations are parallel and don't intersect. In other words, the lines have no point in common, i.e. there's no ordered pair that satisfies both equations.
These are equations of two straight lines. Provided the equations are not of the same or parallel lines, there can be only one ordered pair. So the answer is - not are : (3, 0).
These are equations of two straight lines. Provided the equations are not of the same or parallel lines, there can be only one ordered pair. So the answer is - (not are) : (-1, 3).
That system of equations has no solution. When the two equations are graphed, they turn out to be the same straight line, so there's no such thing as a single point where the two lines intersect. There are an infinite number of points that satisfy both equations.
These are equations of two straight lines. Provided the equations are not of the same or parallel lines, there can be only one ordered pair. So the ordered pair is - not are : (0.5, -1)
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They are all lines. Their equations are written in the slope-intercept form, where we clearly can see if they just intersect, or are perpendicular to each other, or parallel, or coincide.
They are two equations in two unknown variables (x and y), which are inconsistent. That is to say, there is no simultaneous solution. An alternative approach is to say that they are the equations of two lines in the Cartesian plane. The lines are parallel and so they do not meet indicating that there is no simultaneous solution.
3y equal minus 4x minus 16 and 8y equal 6x plus 13 what best describes the graphs of the equations shown below?
The lines are perpendicular.
x + y = 6 x + y = 2 These two equations have no common point (solution). If we graph both equations, we'll find that each one is a straight line. The lines are parallel, and have no intersection point.
A pair of simultaneous equations in two unknowns which are inconsistent - in the sense that there is no solution that simultaneously satisfies both equations. Graphically, the equations are those of two parallel lines (slope = 2). Since, by definition, they cannot meet there is no solution to the system.
There is no pair of numbers (x, y) that fits both of those equations. The graphs of those equations are parallel lines. Since they don't intersect, there's no point on the graph that satisfies both equations.
Solving the simultaneous equations works out as x = -2 and y = -2 So the lines intersect at: (-2, -2)
By graphing the lines on the coordinated plane they will intersect at (2, -4) which is the solution of the equations
x+y=12 is a linear (straight line) equation in the xy-plane. Alternate forms are y=12-x and x=12-y. The form y=12-x is most familiar, and it is a straight line with a slope of -1 that intercepts the y-axis at 12 and the x-axis at 12.
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
There are 0, or no solutions to these equations. If you rearrange each equation to look like an equation of a line, you will have the two lines: y = x -1 and y = x + 1, which are two parallel lines. They do not intersect at any point, so there is no solution.
48 / 2(9+3) = 48 / (2x12) = 48 / 24 = 2.
Does the system of equations have no solution one solution or infinitely many solutions y plus x equals 4 y - 4 equals x?
y + x = 4 y - 4 = x y = -x + 4 y = x + 4 Since the slopes of the lines are negative reciprocals, the lines are perpendicular. Both lines passes through (0, 4), the y-intercept point. Therefore, the system of equations has one solution, (0, 4).
2x - 3y = 2 The graph of this equation is a straight line, which crosses the y-axis where [ y = -2/3 ] and has a slope of 2/3 . x + 2y = 8 The graph of this one is also a straight line, which crosses the y-axis where [ y = 4 ] and has a slope of -1/2 .
x = 3 and y = 2 so the lines intersect at the point (3, 2)
What are the equations of the lines perpendicular to the line 3x-y plus 6 equals 0 and passing at a distance plus -3 from the origin?
The question is not quite clear but one equation will be y = 3x+6 and the other equation will have a slope of minus 1/3
The system of equations is written like this: x+10=y and y-x=-6. In order to determine whether or not the two lines are parallel, we must convert the equations into slope-intercept form and compare the slopes. 1st Equation: x+10=y y=x+10 Well, that was easy. 2nd Equation: y-x=-6 y=x-6 Now, both equations have the same coefficient by x, which is 1. This means that the two lines have the same slope. However, the y-intercepts of 10 and… Read More
With out any equality signs and not knowing the plus or minus values of some of the given terms they can't be considered to be straight line equations.
Which best describes the effect on the graph of y equals 4x plus 8 if the y-intercept is changed to -3?
If you were to graph both equations side by side, you would see that they are parallel lines. Both equations have the same slope it is just that the line would be moved down in the graph because of the intercept change.
What is the correct classification of this system of equations -2x plus y equals 7 3y equals 6x plus 4?
Inconsistent linear equations in two variables.
Without any equality signs they can't be considered to be equations.
Which of the lines does not intersect the line y -2x plus 3 a y 2x b y 2x-3 c y 2x plus 3 d y -2x-3?
Without any equality signs the given expressions can't be considered to be straight line equations but in general parallel straight line equations will have the same slope but different y intercepts.
3x8 is 24 and 2x12 is 24 3/24 is 1/8th 4/24 is 2/12th 7/24 is therefore the answer
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution.
Its actually an R but its soccer match
There is only one equation, so it's not a system of equations.
When x = -2 then y = 4 which is the common point of intersection of the two equations.
Since these are linear equations, that means that you have two parallel lines if you graph it. Solving algebraically, you get something like 7 = 0, which means that no matter what value you assign to x or to y, it is not a solution. Since these are linear equations, that means that you have two parallel lines if you graph it. Solving algebraically, you get something like 7 = 0, which means that no… Read More
When talking about a "system of equations", you would normally expect to have two or more equations. It is quite common to have as many equations as you have variables, so in this case you should have two equations.
Does this system of equations have one solution no solutions or an infinite number of solutions 2x - y equals 8 and x plus y equals 1?
Solve both equations for y, that is, write them in the form y = ax + b. "a" is the slope in this case. Since the two lines have different slopes, when you graph them they will intersect in exactly one point - therefore, there is one solution.
None. They're the equations of parallel lines, so there's no single pair of numbers for 'x' and 'y' that satisfies both of them.
Without any equality signs and not knowing the plus or minus values of the given terms they can't be considered to be straight line equations and so therefore no solutions are possible.
No, they do not.
What is b for these two perpindicular equations 3x plus y-8 equals 0 and -2x plus by plus 9 equals 0?
3x + y - 8 = 0 -2x + by + 9 = 0 y = -3x + 8 by = 2x - 9 y = -3x + 8 y = (2/b)x - 9/b Since the lines, represented by these equations, are perpendicular, their slopes are negative reciprocal of each other. So that 2/b must be equal to 1/3. 2/b = 1/3 b = 6
There is only one line in the x-y plane and that is a straight line with a gradient of -1, passing through the point (0, 10)