The three nines and two eights win, because the higher three of kind is stronger.
Three aces and two eights is a full house. Three Aces and two nines would win. As would three aces and two kickers 10 or higher.
In poker, yes.
No.
3 x 6 = 18 18 / 8 = 2.25 Therefore, 3 x 6 = 2.25 x 8
3Q and 2 nines aka Queens full of Nines. Basically a full house is: 3 Cards + 2 cards. The full house rank is based upon the 3 cards; the higher the better. Lets give an example: AAA99 = Aces full of 9s 999AA = Nines full of Aces The aces full is better, and another example (If both players have Sixes full of X; then the X comes in to play; kind of like a kicker comes into play with pairs) 666QQ = Sixes full of Queens. 666KK = Sixes full of Kings. The 666KK hand would be better.
if 4 and eight eights is subtracted by 3 and three eights, then you get 1 and five eights
Converting all to eights, it gives three eights minus six eights, so the answer is minus three eights.
They can't - three nines equals 27.
the three sixes are in the w the dot on the i and on the y
Three sixes is eighteen which is an integer, not a fraction.
Three Eights
three eights