BB DJ, also known as BB No Money, is the stage name of Canadian rapper and singer Alexander Leon. His parents are of diverse backgrounds; his mother is of Filipino descent and his father is of British descent. This multicultural heritage has influenced his music and artistic style.
Hey there. To answer this accurately, i would need to know the genotypes of both parents. I'll show you a trick that works them out in a flash. A phenotype is the result of a genotype, which is the result of 2 alleles. Say if both parents were HOMOZYGOUS for brown hair, with their genotype would be BB, BB. Use a trick called a punnet square to answer this; _|B |B | B|BB|BB| <-- not the best punnet square, but the top row shows the first parents B|BB|BB| genotype (BB) and the side shows the second's. (BB) The cross of this shows all the children will have brown hair, as inherited from each parent. If the Mother had HOMOZYGOUS brown hair (BB), and the father had HETEROZYGOUS brown hair (Bb) the results would be 100% Brown hair too, because the brown hair gene (B) is dominant over the non brown hair gene (b). Below; _|B |B | B|BB|BB| <--- this shows the cross gives a 50% chance to be Homozygous for brown b|Bb|Bb| hair but 50% heterozygous for brown hair, but carrying a non- brown hair gene. If we cross 2 heterozygous parents, the results are shown: _|B |b | B|BB|Bb| b|bB|bb| <----- This shows the child has a 75% chance of having brown hair (either (BB or bB, Bb) and 25% of being non-brown (bb)). This can be used in any gene cross, but you must keep in mind that one gene will be dominant and one will be recessive. I used the brown hair gene as an example here, as I don't know whether it may be dominant or recessive to other hair colours. Also, if you were after a global statistic, I wouldn't know. I hope this helps you. Fletch
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
If both parents are genotype BB, the child can only be blood type B. The child's genotype would also be BB.
BB guns are a toy but Only 10 and add but if you are young it is up to your parents
If both parents are black-haired guinea pigs and the black coat color is dominant, they could either be homozygous (BB) or heterozygous (Bb) for the black coat gene. If both are heterozygous (Bb), the offspring ratio would typically be 25% homozygous black (BB), 50% heterozygous black (Bb), and 25% brown (bb). Therefore, among the 20 offspring, we would expect around 15 to be black (BB or Bb) and about 5 to be brown (bb) if the parents are Bb. If both parents are homozygous (BB), all offspring would be black.
Your parents will decide.
Mr and Mrs King
Yes- with the permission of your parents.
If both brown-haired parents carry a recessive gene for blonde hair (genotype Bb), they can produce offspring with the following combinations: BB, Bb, Bb, and bb. The only combination that results in blonde hair is bb. Therefore, 25% of the offspring will have blonde hair.
Depends on the parents and local laws (if any).
If one parent is BB (homozygous dominant) and the other is Bb (heterozygous), the possible genotypes for their children are BB and Bb. This means that all children will either be BB or Bb, resulting in a 50% chance for each genotype. Consequently, all children will express the dominant trait associated with the B allele.
Both parents were heterozygous (Bb). The offspring would statistically be: BB, Bb, Bb, and bb. All but the bb offspring would be black and the bb would be brown.
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
Depends on your skills, size and parents.