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If one parent is BB (homozygous dominant) and the other is Bb (heterozygous), the possible genotypes for their children are BB and Bb. This means that all children will either be BB or Bb, resulting in a 50% chance for each genotype. Consequently, all children will express the dominant trait associated with the B allele.
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A child has blue eyes both parents have brown eyes are bith parents heterozygotes for brown eyes?
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
What is the probability that the children will be heterozygous?
Being born with six fingers is actually a dominant trait and the probability of the children would be 75% with six fingers and 25% with five fingers if both parents were heterozygous for that trait. If both parents were homozygous dominant for that trait then there is a 100% probability of the children being born with six fingers.
How can both of your parents have brown eyes and you have blue eyes?
Yes. Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
Can two parents with brown eyes have two sons who both have blue eyes?
Yes. Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
Can a child get blue eyes if parents ars brown?
Yes. Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
In the following couples what color eyes with the children have 1. The mother has brown eyes and is Bb. The father has blue eyes and is bb 2. The mother has blue eyes and is bb the father has blue ey?
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
What are the alleles for dominant brown eyes?
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
What color eye will your baby have if the dad has blue and the mom has brown?
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
What is the odd of your baby have blue eyes when you have blue eyes and mate has brown?
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
What color eyes will baby have if mother has brown eyes and father has blue eyes?
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
What is the probability that the baby would be homozygous if mom has brown eyes and dad has blue eyes?
Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
You fathered a brown eyed daughter and you have blue eyes is this possible?
Sure. Brown eye gene = B Blue eye gene = b Each person has two copies of the eye color gene in their genome, one inherited from each parent. Now if both parents only carry the gene for brown eyes, BB and BB, then their child will receive one B from each parent, ending up as BB. The same works for blue eyes, if that's the only gene both parents carry, bb and bb. Each parents gives on b to the child, who ends up as bb. If you have one parent who only has the gene for brown eyes, BB, and one parent who only has the gene for blue eyes, bb, then all the children will have brown eyes. Example: One parent gives a B, the other gives a b. Bb = brown eyes. Here's why: When you have two alleles (coding sequences) from genes that are at odds with each other, one version will override the the other. When dealing with eye color, B always dominates b. But these children now carry the b gene in them, and could pass it down to their own children. Some of them, depending on the other parent, could end up with blue eyes. If one parent is Bb, and the other is bb, then each time they have a child, there is a 50% chance it will have blue eyes. Example: First parent is Bb, second parent is bb, then their children will end up as either Bb, bb, Bb, bb. If both parents carry the genes for brown eyes and blue eyes, then each time they have a child, there is a 25% chance it will have blue eyes. Example: First parent is Bb, second parent is Bb, then their children will end up as either BB, Bb, Bb, bb.
