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Who do solve FLT some lines?

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Anonymous

12y ago
Updated: 8/20/2019

I like back into multidimensional space where were born to be sleeping forever thousands autumn.

Pierre De Fermat's last theorem.

The conditions.

x,y,z,n are the integers >0 and n>2.

z^n=/x^n+y^n.

Assumptions

z^3=x^3+y^3.

Therefore

z=(x^3+y^3)^1/3.

I define .

F(x,y)=(x^3+y^3}^1/3 - [ (x-x-1)^3+(y-x-1)^3]^1/3.

Therefore

[z-F(x,y)]^3={ (x^3+y^3)^1/3 - (x^3+y^3}^1/3 + [ (x-x-1)^3+(y-x-1)^3] ^1/3 }^3={ [(x-x-1)^3+(y-x-1)^3]^1/3 }^3 =(x-x-1)^3+(y-x-1)^3= (y-x-1)^3-1.

Because

[z-F(x,y)]^3=(y-x-1)^3-1 .

Attention

[(y-x-1)^3-1 ] is an integer , [(y-x-1)^3-1 ]^1/3 is an irrational number therefore [(y-x-1)^3-1 ]^2/3 is an irrational number too.

Example

(2^3-1) is an integer , (2^3-1)^1/3 is an irrational number and (2^3-1)^2/3 is an irrational number too.

Because

z-F(x,y)=[y-x-1)^3-1]^1/3.

Therefore

z=F(x,y)+[(y-x-1)^3-1] ^1/3.

Therefore

z^3=[F(x,y)]^3.+3[F(x,y)]^2*[(y-x-1)^3-1]^1/3+3F(x,y)*[(y-x-1)-1]^2/3+[(y-x-1)^3-1].

Therefore

3F(x,y)*[(y-x-1)^3-1]^2/3+[F(x,y)]^3+3[F(x,y)]^2*[(y-x-1)^3-1]^1/3+[(y-x-1)^3-1] - z^3 =0

Because.

z-F(x,y)=[ (y-x-1)^3-1]^1/3.

Therefore

F(x,y)=z - [(y-x-1)^3-1]^1/3.

Therefore

3F(x,y)*[(y-x-1)^3-1]^2/3

=3z*[(y-x-1)^3-1]^2/3 -3[(y-x-1)^3-1].

Therefore.

3z*[(y-x-1)^3-1]^2/3 - 3[(y-x-1)^3-1]+[F(x,y)]^3+3[F(x,y)]^2*[y-x-1)^3-1]^1/3+[(y-x-1)^3-1] - z^3=0..

Named

[F(x,y)]^3+3[F(x,y)]^2*[(y-x-1)^3-1]^1/3+[(y-x-1)^3-1] - z^3= W.

We have

3z*[(y-x-1)^3-1]^2/3 is an irrational number because z is an integer and had proved [(y-x-1)^3-1]^2/3 is an irrational number.

And

3[(y-x-1)^3-1] is an integer because x,y are the integers.

And

3z*[(y-x-1)^3-1]^2/3 - 3[(y-x-1)^3-1]+[F(x,y)]^3+W=0.

Therefore

an irrational number - an integer+W=0.

Therefore

W is an complex irrational number.

Named

3z*[(y-x-1)^3-1]^2/3 is 3z*B

And

Named

3[(y-x-1)^3-1] is C .

Therefore

3z*B - C +W=0.

Therefore

3z*B=C-W.

Because

z is an integer.

B is an irrational number=[(y-x-1)^3-1]^2/3

Attention

(an integer)^2/3 and (an integer)^2/3 is an irrational number.

W is an complex irrational number.

C is an integer.

Therefore.

an integer*an irrational number=an complex irrational number + an integer.

Unreasonable.

Therefore.

z^3=/x^3+y^3

Similar

z^n=/x^n+y^n.

ISHTAR.

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12y ago

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