3n(n+1] + 5 is the nth term
3n^2+3n+5 I had this question on a test and I don’t know how to solve it but this is the answer
t(n) = 6*n - 1 where n = 1, 2, 3, ...
14+9n
The 'n'th term is [ 13 + 5n ].
It is: 5n+3 and so the next term is 28
58
35 * * * * * That is the next term. The question, however, is about the nth term. And that is 6*n - 1
It is 6n+5 and so the next term will be 35
5, 11, 17, 23, 29
It is 4n -1 and so the next term will be 23
t(n) = 6*n - 1 where n = 1, 2, 3, ...
If you meant: 2 12 22 32 then the nth term = 10n-8
n + 6 * * * * * I suggest you try t(n) = 6n + 5 instead.
The differences are 3, 5, 7, 9,11, ... and the first term is -1; the nth term is: n² - 2
2n +29
14+9n
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].