humpdy dumpdy, and he broke it!! :)
song:
humpdy dumpdy sat on a wall, humpdy dumpdy had a great fall, all the kings horses and all the kings men, put humpdy dumpdy together again.....
kinda a dumb song bt he fell and broke into pieces and everybody put him back together. (its a fairytale type thing)
No
n n n n n n n n n n n n n n n o o o o o o o o o o o o o t t t t t t t t t t t h h h h h h h h h h h h h h i i i i i i i i i i n n n n n n n n n n g g g g g g gg g g g g g g g gg gg g
goat so gas no got not sat mat oat manta sag
n n n n n n n n n n n n n n n o o o o o o o o o o o o o t t t t t t t t t t t h h h h h h h h h h h h h h i i i i i i i i i i n n n n n n n n n n g g g g g g gg g g g g g g g gg gg g
n-o n-o n-o n-o noIn so many ways, no.
No, if f(n) o(g(n)), it does not necessarily imply that g(n) o(f(n)).
P o o n a n n y
o rly?
nose sat son/s ton/s tone tan/s toe/s soe note/s not
L-I-N-D-O or B-O-N-I-T-O (masculine) L-I-N-D-A or B-O-N-I-T-A (feminine)
n-1 (o-o-o-o-o)
An algorithm with a runtime of O(log n) has a faster time complexity compared to an algorithm with a runtime of O(n). This means that as the input size (n) increases, the algorithm with O(log n) will have a more efficient performance than the one with O(n).