Because the sodium chloride solution in this case is isotonic.
In this case sodium chloride form an isotonic solution.
Tween 20. In TBST you add 0.05-0.1/ Tween 20.
The recommended protocol for performing a western blot using the TBST buffer involves transferring proteins from a gel to a membrane, blocking the membrane to prevent non-specific binding, incubating with primary and secondary antibodies, and washing with TBST buffer to remove excess antibodies.
TBST and PBST are both commonly used solutions in laboratory experiments, but they have different compositions. TBST contains Tris-buffered saline and Tween-20, while PBST contains Phosphate-buffered saline and Tween-20. These solutions are used for washing and blocking steps in experiments, with TBST being more commonly used in protein-related experiments and PBST being more commonly used in nucleic acid-related experiments.
PBST and TBST solutions are both used in laboratory experiments for washing and blocking proteins on membranes. The main difference between the two is the type of detergent used. PBST contains Tween-20, while TBST contains Triton X-100. Tween-20 is milder and less likely to interfere with protein binding, making PBST suitable for delicate proteins. Triton X-100 is stronger and more effective at removing stubborn contaminants, making TBST better for tougher samples.
NaCl doesn't neutralize sulfuric acid.
You need 58,44 mg of ultrapure NaCl; dissolve in demineralized water, at 20 0C, in a thermostat, using a class A volumetric flask of 1 L.
To determine this, you need the concentration of the NaCl solution. Once you have that, you can use the stoichiometry of the reaction between AgNO3 and NaCl to calculate the volume of 0.117 M AgNO3 needed. The balanced chemical equation for this reaction is: AgNO3 + NaCl → AgCl + NaNO3.
To find the moles of NaCl needed, first convert 140 mM to M by dividing by 1000. Then, use the formula moles = Molarity x Volume (in liters) to calculate the moles required. In this case, the calculation would be: 0.140 mol/L x 1 L = 0.140 moles of NaCl.
1 mg/l = 1ppm1 g/l = 1000 ppmNaCl ----------------> Na+ + Cl-58.5 g NaCl gives 22.989 g Na+(58.5 / 22.989) = 2.545 g of NaCl is required to give 1 g of Na+When 2.545 g of NaCl is dissolved in 1 liter water will yield 1000 ppm of Na+ in NaCl solution.
Molar mass of NaCl =~58.4 g/mole0.1 N NaCl = 0.1 moles/liter To make 1 liter of 0.1N NaCl thus requires 0.1 moles/liter = 0.1 moles x 58.4 g/mole = 5.84 moles Dissolve 5.84 g (6 g using 1 sig. fig.) in a final volume of 1 liter to make 0.1N NaCl
The answer is 0,1648 g NaCl.