Because the sodium chloride solution in this case is isotonic.
In this case sodium chloride form an isotonic solution.
Tween 20. In TBST you add 0.05-0.1/ Tween 20.
NaCl doesn't neutralize sulfuric acid.
You need to know the amount of NaCl.
200 milliliters
You need 58,44 mg of ultrapure NaCl; dissolve in demineralized water, at 20 0C, in a thermostat, using a class A volumetric flask of 1 L.
2g
It depends on the final solution Volume you want to prepare. For 100ml of a 6M NaCL solution, you add 35.1g of NaCl to water until you reach 100ml. Dissolve and autoclave for 15 mins.
1 mg/l = 1ppm1 g/l = 1000 ppmNaCl ----------------> Na+ + Cl-58.5 g NaCl gives 22.989 g Na+(58.5 / 22.989) = 2.545 g of NaCl is required to give 1 g of Na+When 2.545 g of NaCl is dissolved in 1 liter water will yield 1000 ppm of Na+ in NaCl solution.
Molar mass of NaCl =~58.4 g/mole0.1 N NaCl = 0.1 moles/liter To make 1 liter of 0.1N NaCl thus requires 0.1 moles/liter = 0.1 moles x 58.4 g/mole = 5.84 moles Dissolve 5.84 g (6 g using 1 sig. fig.) in a final volume of 1 liter to make 0.1N NaCl
The answer is 0,1648 g NaCl.
For 100 mM NaCl solution in 1L: Formula weight: 58.44 g/L Answer: 5.844 g/L if you want in 500 mL---2.922 g if you want in 250 mL---1.461 g if you want in 100 mL---584.4 mg