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Q: Why Pb2 plus is more stable than Pb4 plus?
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Pb2 plus yields Pb4 plus is this oxidation or reduction?

oxidation


Does Pb2 plus react with oxygen?

Yes. They react to form lead (II) oxide.


The reaction pbbr2s pb2 plus aq plus 2br-aq has reached saturation with concentrations pb2 plus equals 2.5 x 10-3 and br- equals 5.0 x 10-2 what is the value of ksp for pbbr2 at this temperatur?

6.3 x 10-6


Why is lead chloride a powerful oxidizing agent?

The oxidation state 4+ is not stable in PbCl4; the reaction is:Pb4+ + 2 e---------Pb2+


What is the name for Pb2 plus and O2-?

Lead (IV) ion


The pb k-egde xanes data reveals that pb is in a mixed valence state of pb4 plus and pb2 plus however in literature pb is claimed to be in pb2 plus state the pb 6s2 electrons hybridize with the o 2p?

The Pb K-egde Xanes data reveals that Pb is in a mixed valence state of Pb4+ and Pb2+. However in literature Pb is claimed to be in Pb2+ state. The Pb 6s2 electrons hybridize with the O 2p electrons to form strong covalent bonding which results in the relative displacement of Pb cage with respect to the O-octahedron. This results in increase ferroelectric properties of PbTiO3.However the question is that in the covalent state of the Pb2+ will it appear as Pb4+ state in the Pb K-edge? The reason argued here is that the Pb will lose the 6s2 electrons to form the bond and hence appear to be Pb4+. Hence the argument placed by this pool of thought is from the EXAFS data what appears to be Pb4+ is actually the covalently bonded Pb2+ while what appears to be Pb2+ is actually the ionic type Pb2+.What is the oxidation state of Pb and Ti in PbTiO3 ?


What is the correct cell notation for the redox reaction 3Pb2 plus aq plus 2Cr s 3Pb s plus 2Cr3 plus aq?

Cr(s) | Cr3+(aq) Pb2+(aq) | Pb(s)


What is the symbol for lead ion?

Pb2+


What is the chemical formula for lead salt?

Pb2+


What is the formula for plumbous ion?

Formula: Pb2+


PbBr2 soluble in water?

It is very slightly soluble in water.In a saturated solution:[Pb2+] = 1.2x10-2 mol/L[Br-] = 2.4x10-2 mol/Lbecause [Pb2+]*[Br-]2 = Ks = 6.3*10-6 and [Br-] = 2*[Pb2+]


What is mean by PBM in mass transfer?

It is the log mean value of the inert B in counterdiffusion usually used to find a flux. P = pA1 + pB1 = pA2 + pB2 thus, pB1 = P - pA1, and pB2 = P - pA2, so: pBM = [pB2 - pB1]/ln(pB2/pB1) = [pA1 - pA2]/ln[(P-pA2)/(P-pA1)] happy engineering :)