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Why an ammeter is likely to burn out if connected in parallel combination?
Wiki User
∙ 11y ago
ameter has a low resistance so if it is placed in parallel with the load then it will experiance voltage as much as the load and according to equation
power=v2/r
the power will be very high as high v or low r both favors for a high power dissipation .
but on a series combination most of the voltage drop will be on load the ameter will not have a high power dissipation
Wiki User
∙ 11y ago
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