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Because females have TWO X chromosomes. Males only have one. that means if the recessive gene is on the X chromosome it becomes evident phenotypically.
The recessive genes are present on the X-chromosome. Female chromosome has another X-chromosome, which is dominant and masks the defective gene, and it is quite rare that both the chromosomes have recessive alleles. But, in males, the Y-chromosome has nothing to over mask the defective gene and the abnormality shows up in the form of the disease.
Because males have XY configuration of sex chromosomes and females XX. So in xy situation even the recessive gene can express. That is why sex-linked characters in males are more common than females.
A sex linked dominant trait could be on the X chromosome of either parent and the phenotype of any individual carrier would be that of the dominant trait. A father with the dominant characteristic on his single X chromosome would produce daughters that are 100% carriers and would not pass the characteristic on to his sons. A mother who is a dominant X linked carrier would pass the dominant characteristic on to half hersons and half her daughters all of which would show the trait phenotypically. A sex linked recessive father would produce 100% carrier daughters. His sons would not get the recessive allele from him. A sex linked recessive carrier (heterozygous) mother would pass the trait on to 50% of her children and 50% of her sons would show the recessive trait genetics.
Color blindness is a recessive sex linked trait.
X-linked are not recessive nor dominant. X-linked just do not show. On the sex-linked chromosomes the Y chromosome of the X-Y pair dominates the trait whether its recessive or dominant!Actually, all x-linked alleles are expressed because males only have one x-chromosome, so whatever is there, dominant or recessive, is expressed.
color blindness is one
No, it is an example of sex-linked recessive inheritance.
Because males have an X and Y chromosome. If the trait is X-linked (recessive), there is nothing to mask the expression. On the other hand if a woman has an x-linked recessive allele and a dominant one, the dominant trait is the one that will be expressed.
Hemophilia is an X-linked recessive disease which means the disease can manifest only if the genes on both chromosomes are affected. As males have only one X chromosome the disease always manifests. It is possible for a female to be affected but it is very rare.
Because females have TWO X chromosomes. Males only have one. that means if the recessive gene is on the X chromosome it becomes evident phenotypically.
The recessive genes are present on the X-chromosome. Female chromosome has another X-chromosome, which is dominant and masks the defective gene, and it is quite rare that both the chromosomes have recessive alleles. But, in males, the Y-chromosome has nothing to over mask the defective gene and the abnormality shows up in the form of the disease.
Males have only one X chromosome, so a recessive X-linked trait will be displayed in the phenotype [visible on the outside]. Females have two X chromosomes, so both of the chromosomes must have the trait for it to be displayed on the phenotype.
Because males have XY configuration of sex chromosomes and females XX. So in xy situation even the recessive gene can express. That is why sex-linked characters in males are more common than females.
Because they olny have one X chromosome.
Because they olny have one X chromosome.
A sex linked dominant trait could be on the X chromosome of either parent and the phenotype of any individual carrier would be that of the dominant trait. A father with the dominant characteristic on his single X chromosome would produce daughters that are 100% carriers and would not pass the characteristic on to his sons. A mother who is a dominant X linked carrier would pass the dominant characteristic on to half hersons and half her daughters all of which would show the trait phenotypically. A sex linked recessive father would produce 100% carrier daughters. His sons would not get the recessive allele from him. A sex linked recessive carrier (heterozygous) mother would pass the trait on to 50% of her children and 50% of her sons would show the recessive trait genetics.