X-linked are not recessive nor dominant. X-linked just do not show. On the sex-linked chromosomes the Y chromosome of the X-Y pair dominates the trait whether its recessive or dominant!
Actually, all x-linked alleles are expressed because males only have one x-chromosome, so whatever is there, dominant or recessive, is expressed.
Recessive alleles are expressed if there is no dominant allele (of the same gene) present. This can be for two reasons, because the other allele is also recessive, or because there is no other allele (such as X-linked genes, which males only have one copy of).
Color blindness is an inherited trait that can be passed on through reproduction but it has some peculiarities. It is recessive and not very prevalent in the gene pool. Because of this, color blindness does not appear very often in the population. In addition, it is a sex-linked gene on the X chromosome. Thus males only have one gene to express color vision. If it happens to be the recessive allele, then males are color blind. Females, on the other hand, must have both alleles recessive in order to be color blind.source: ciese.org/curriculum/genproj/activity35.html
Because males have an X and Y chromosome. If the trait is X-linked (recessive), there is nothing to mask the expression. On the other hand if a woman has an x-linked recessive allele and a dominant one, the dominant trait is the one that will be expressed.
A trait is sex-linked dominant if it appears in every generation and affects both males and females. It is sex-linked recessive if it skips generations, more common in males, and passed from carrier females to affected males. Mendelian inheritance patterns can help determine if a trait is sex-linked dominant or sex-linked recessive.
Most copies of harmful recessive alleles are carried by unaffected carriers who are phenotypically normal but carry one copy of the allele. When two carriers have offspring, there is a 25% chance the child will inherit two copies of the harmful allele, leading to a genetic disorder.
Recessive traits on X chromosome are expressed in males because they have only one copy of X chromosome. If they have any recessive gene it will be expressed. In female both the genes should be recessive then only the recessive character will be expressed.
The recessive genes are present on the X-chromosome. Female chromosome has another X-chromosome, which is dominant and masks the defective gene, and it is quite rare that both the chromosomes have recessive alleles. But, in males, the Y-chromosome has nothing to over mask the defective gene and the abnormality shows up in the form of the disease.
No, it is an example of sex-linked recessive inheritance.
If a daughter expresses an X-linked recessive gene, she inherited the trait from her father who carries the gene on his X chromosome. Since males only have one X chromosome, if they have the gene, daughters will always inherit it from their father.
Being Colorblind means you recieved 2 recessive alleles from you parents. So that means the mother and father must of had 2 recessive alleles. Also Colorblindness is more common in males.
A sex linked dominant trait could be on the X chromosome of either parent and the phenotype of any individual carrier would be that of the dominant trait. A father with the dominant characteristic on his single X chromosome would produce daughters that are 100% carriers and would not pass the characteristic on to his sons. A mother who is a dominant X linked carrier would pass the dominant characteristic on to half hersons and half her daughters all of which would show the trait phenotypically. A sex linked recessive father would produce 100% carrier daughters. His sons would not get the recessive allele from him. A sex linked recessive carrier (heterozygous) mother would pass the trait on to 50% of her children and 50% of her sons would show the recessive trait genetics.
Because females have TWO X chromosomes. Males only have one. that means if the recessive gene is on the X chromosome it becomes evident phenotypically.