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The short answer is because Be(OH)2 reacts with strong acids, like H2SO4, to produce Be(SO4) and 2H2O. On the other hand, Be is very different than the other members Mg, Ca, Sr, and Ba in that it forms covalent bonds. This is evident from the much lower boiling and melting point of its salts compared to the other group 2 elements. In water Be(+2) exists as [Be(H2O)4](+2). In the presence of strong alkali this species undergoes reaction to give [Be(H2O)2(OH(-1)2] displacing two moles of water. This species is insoluble and precipitates. The addition of further strong alkali gives [Be(OH(-1))4](-2)] which is water soluble. Aluminum behaves similarly.

One should deal with any beryllium compounds "theoretically" never experimentally unless the lab is especially equipped to handle beryllium. It is not only carcinogenic, its compounds are chemically extremely acutely toxic

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Q: Why beryllium oxide is amphoteric in nature?
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