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Explain why friction changes the the Velocity of objects and why friction can make observing Newton's first law of motion difficult?
newtons laws are idealised and don't involve external forces like friction and air resistance
What unit do you measure friction in?
you measure friction in Newtons
How is algebra used in skydiving?
Fnet=Fgravity-Fair resistance At terminal velocity Force Net = 0 during this time Fgravity = Fair resistance if you weight is 85kg Fgravity = Mass x G = 85x 9.8 = 833N your at terminal velocity when Air resistance is equal to 833 Newtons
The blank is reached when the force of gravity is balanced by air resistance the size of the air resistance force depends on the shape of an object and it's speed?
yes force down in newtons = (mass * acceleration due to gravity) constant force up in newtons = ( velocity^2 * drag coefficient) increases with velocity until terminal velocity reached, forces balance , no further acceleration. if mass(m) and terminal velocity(tv) are known, drag coefficient(dc) can be calculated. if : (m * g) = (tv^2 * dc) so: dc = (m * g )/( tv^2) drag coefficient is dependent on shape and texture, and is exclusive to each object. air resistance to motion increases as to the square of velocity
What is the net force that acts on a 10-N falling object when it encounters 4 N of air resistance?
Fnet= mg-R Fnet= (10-4)= 6 So the net force is 6 N. :)
What is an example of terminal velocity?
An example would be "any object that is moving through the air, water or other substance at a rate such that it cannot possibly go faster without additional force being applied." "Terminal Velocity" in dropping a rock from an airplane might mean "the fastest the rock can possibly fall on its own." Once the rock reached that velocity, it would not be able to go faster despite that it had accelerated to that point without additional force (or increased gravity) being applied to the rock. rock from plane when force down = force up force down = mg (newtons) force up = force of air resistance (velocity ^2* drag coefficient ) newtons. you can use known terminal velocity to calculate drag coefficient if mass is known.
How much force does a rain drop have?
A raindrop's force is typically very small and varies depending on its size and speed. On average, a raindrop falling at terminal velocity has a force equivalent to about 0.01 Newtons.
How does friction prevent us from observing Newton's First Law in the real world?
As we roll down a marble on a horizontal floor with some velocity then it is expected to keep rolling on with the same velocity (both magnitude and direction to be constant). But it is brought to rest. So out of two parts in Newtons's first law, the second part cannot be easily demonstrated. That part says that unless an external force acts the uniformly moving body continues to do so.
How do the resistance and the weight of a falling object compare when terminal speed is reached?
Air resistance doesn't change with weight. It changes with speed and shape. More speed, more air resistance. If the shape has a lot of surface are to drag the air, it is more resistant, but this factor does not change with weight or speed. This is why terminal velocity is possible. As the object falls, its speed increases, so its resistance increases also, because resistance depends directly on speed. But as this resistance is increasing, the gravity is staying the same. So, eventually, resistance catches up with gravity and cancels it out, causing an end to acceleration, or constant speed.
Why does a parachutist have two terminal velocities?
Because the drag coefficient increases when the chute opens..Force down (newtons) = mass (m) * acceleration due to gravity (g)Force up (newtons) = velocity2 * drag coefficient.Terminal velocity is where up and down forces balance.Say mass (m) = 100 kg, g = 9.82, then force down = m * g = 982 newtons, say terminal velocity (v) prior to chute opening = 70 m / s, then force down = force up so 982 = v2 * drag coefficient, so drag coefficient = 982 / 4900 = 0.2without chute.Terminal velocity with chute open, say 8 metres / sec, so drag coefficient= 982 / 64 = 15.34 with chute open.
When a 10 newton falling body encounters 4 newtons of air resistant the net force on the body is?
6 newtons, so it keeps accelerating. As it does, the air resistance increases until it reaches 10 newtons so then the net force is zero and then the fall continues at constant speed (the terminal velocity).
What forces work on a skydiver?
(standard air pressure and gravity)>(Constant) Force down (newtons) = mass * acceleration due to gravity>Say 70 kg skydiver @ 9.82 m/s/s = 70 * 9.82 = 687.4 newtons>Force up (newtons) = velocity 2 * drag coefficient (say 0.16 typical)>Terminal velocity (when forces balance) 687.4 = v 2 * 0.16Terminal velocity = square root (687.4 / 0.16)= 65.546 metres per second ( 147 mph) terminal velocity
