This question does not make sense
newtons laws are idealised and don't involve external forces like friction and air resistance
(standard air pressure and gravity)>(Constant) Force down (newtons) = mass * acceleration due to gravity>Say 70 kg skydiver @ 9.82 m/s/s = 70 * 9.82 = 687.4 newtons>Force up (newtons) = velocity 2 * drag coefficient (say 0.16 typical)>Terminal velocity (when forces balance) 687.4 = v 2 * 0.16Terminal velocity = square root (687.4 / 0.16)= 65.546 metres per second ( 147 mph) terminal velocity
you measure friction in Newtons
Fnet=Fgravity-Fair resistance At terminal velocity Force Net = 0 during this time Fgravity = Fair resistance if you weight is 85kg Fgravity = Mass x G = 85x 9.8 = 833N your at terminal velocity when Air resistance is equal to 833 Newtons
yes force down in newtons = (mass * acceleration due to gravity) constant force up in newtons = ( velocity^2 * drag coefficient) increases with velocity until terminal velocity reached, forces balance , no further acceleration. if mass(m) and terminal velocity(tv) are known, drag coefficient(dc) can be calculated. if : (m * g) = (tv^2 * dc) so: dc = (m * g )/( tv^2) drag coefficient is dependent on shape and texture, and is exclusive to each object. air resistance to motion increases as to the square of velocity
Fnet= mg-R Fnet= (10-4)= 6 So the net force is 6 N. :)
6 newtons, so it keeps accelerating. As it does, the air resistance increases until it reaches 10 newtons so then the net force is zero and then the fall continues at constant speed (the terminal velocity).
As we roll down a marble on a horizontal floor with some velocity then it is expected to keep rolling on with the same velocity (both magnitude and direction to be constant). But it is brought to rest. So out of two parts in Newtons's first law, the second part cannot be easily demonstrated. That part says that unless an external force acts the uniformly moving body continues to do so.
An example would be "any object that is moving through the air, water or other substance at a rate such that it cannot possibly go faster without additional force being applied." "Terminal Velocity" in dropping a rock from an airplane might mean "the fastest the rock can possibly fall on its own." Once the rock reached that velocity, it would not be able to go faster despite that it had accelerated to that point without additional force (or increased gravity) being applied to the rock. rock from plane when force down = force up force down = mg (newtons) force up = force of air resistance (velocity ^2* drag coefficient ) newtons. you can use known terminal velocity to calculate drag coefficient if mass is known.
constant force down (newtons) = mass (kg) * acceleration due to gravity ((m/s)/s) > variable force up (newtons) = velocity2 * drag coefficient > terminal velocity is where forces balance
Air resistance doesn't change with weight. It changes with speed and shape. More speed, more air resistance. If the shape has a lot of surface are to drag the air, it is more resistant, but this factor does not change with weight or speed. This is why terminal velocity is possible. As the object falls, its speed increases, so its resistance increases also, because resistance depends directly on speed. But as this resistance is increasing, the gravity is staying the same. So, eventually, resistance catches up with gravity and cancels it out, causing an end to acceleration, or constant speed.
Simplified: The coefficient of dynamic (moving) friction, is derived from: > coefficient = force resisting motion (newtons) / force of object on surface (newtons)