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Why do people text k?

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Anonymous

15y ago
Updated: 8/18/2019

Because typing "k" is shorter than typing ok, okay, or alright, and still accomplishes the same purpose.

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Wiki User

15y ago

What else can I help you with?

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Why do people say kk instead of k in text language meaning ok?

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How do you give hyperlink within excel sheet?

yes you can use hyperlink in MS Excel, Press Ctrl + K key on keyboard to put hyperlink. Also, you can have this to link between MS Excel files or website or email Sarfaraz Ahmed http://findsarfaraz.blogspot.com


What is the function of control k?

Control K is typically used in text editing software to cut text (similar to the command X function). When you press Control K, it cuts the selected text and stores it in the clipboard for pasting elsewhere.


What is the pressure exerted by 2.26 mol of gas in a 2.92 L container at 32C?

To find the pressure exerted by the gas, we can use the Ideal Gas Law, which is ( PV = nRT ). Here, ( n = 2.26 ) mol, ( R = 0.0821 , \text{L} \cdot \text{atm} / (\text{mol} \cdot \text{K}) ), and ( T = 32°C = 305 , \text{K} ). Plugging in the values, we get ( P = \frac{nRT}{V} = \frac{(2.26 , \text{mol}) \cdot (0.0821 , \text{L} \cdot \text{atm} / (\text{mol} \cdot \text{K})) \cdot (305 , \text{K})}{2.92 , \text{L}} \approx 18.1 , \text{atm} ).


What does K mean in text messages?

It means 'okay'.


How many unique substrings of length k can be found within the given text?

The number of unique substrings of length k in the text can be calculated using the formula: (n-k1), where n is the length of the text.


What is the value for G at 700 K if H -92 kj mol and S -0.199 kj mol-k?

To calculate the Gibbs free energy (G) at 700 K, we can use the formula: ( G = H - TS ). Given that ( H = -92 , \text{kJ/mol} ) and ( S = -0.199 , \text{kJ/(mol·K)} ), we first calculate ( TS = 700 , \text{K} \times -0.199 , \text{kJ/(mol·K)} = -139.3 , \text{kJ/mol} ). Then, substituting into the Gibbs equation: [ G = -92 , \text{kJ/mol} - (-139.3 , \text{kJ/mol}) = 47.3 , \text{kJ/mol}. ] Thus, the value for G at 700 K is 47.3 kJ/mol.


What is the heat when 100.0 g of Mg cool from 725 K to 552 K?

To calculate the heat released when magnesium (Mg) cools from 725 K to 552 K, we use the formula ( q = m \cdot c \cdot \Delta T ), where ( m ) is the mass, ( c ) is the specific heat capacity of magnesium (approximately 1.02 J/g·K), and ( \Delta T ) is the change in temperature. The temperature change ( \Delta T ) is ( 552 , \text{K} - 725 , \text{K} = -173 , \text{K} ). Substituting the values, ( q = 100.0 , \text{g} \cdot 1.02 , \text{J/g·K} \cdot (-173 , \text{K}) ), which calculates to approximately -17656.6 J. Therefore, the heat released is about 17.7 kJ.


What does K mean in text?

K means "okay" KK is also another way of saying it.


What is the pressure of a sample of butane containing 2.10 moles present in a 60.0 L vessel a 2.0 celsius?

To find the pressure of the butane sample, we can use the ideal gas law equation ( PV = nRT ). First, convert the temperature from Celsius to Kelvin: ( 2.0 , \text{C} + 273.15 = 275.15 , \text{K} ). Using the ideal gas constant ( R = 0.0821 , \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} ), we can rearrange the equation to solve for ( P ): [ P = \frac{nRT}{V} = \frac{2.10 , \text{mol} \times 0.0821 , \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} \times 275.15 , \text{K}}{60.0 , \text{L}} \approx 0.96 , \text{atm}. ] Thus, the pressure of the butane sample is approximately 0.96 atm.