Because typing "k" is shorter than typing ok, okay, or alright, and still accomplishes the same purpose.
ok cool
k
k
yes you can use hyperlink in MS Excel, Press Ctrl + K key on keyboard to put hyperlink. Also, you can have this to link between MS Excel files or website or email Sarfaraz Ahmed http://findsarfaraz.blogspot.com
Control K is typically used in text editing software to cut text (similar to the command X function). When you press Control K, it cuts the selected text and stores it in the clipboard for pasting elsewhere.
To find the pressure exerted by the gas, we can use the Ideal Gas Law, which is ( PV = nRT ). Here, ( n = 2.26 ) mol, ( R = 0.0821 , \text{L} \cdot \text{atm} / (\text{mol} \cdot \text{K}) ), and ( T = 32°C = 305 , \text{K} ). Plugging in the values, we get ( P = \frac{nRT}{V} = \frac{(2.26 , \text{mol}) \cdot (0.0821 , \text{L} \cdot \text{atm} / (\text{mol} \cdot \text{K})) \cdot (305 , \text{K})}{2.92 , \text{L}} \approx 18.1 , \text{atm} ).
It means 'okay'.
The number of unique substrings of length k in the text can be calculated using the formula: (n-k1), where n is the length of the text.
To calculate the Gibbs free energy (G) at 700 K, we can use the formula: ( G = H - TS ). Given that ( H = -92 , \text{kJ/mol} ) and ( S = -0.199 , \text{kJ/(mol·K)} ), we first calculate ( TS = 700 , \text{K} \times -0.199 , \text{kJ/(mol·K)} = -139.3 , \text{kJ/mol} ). Then, substituting into the Gibbs equation: [ G = -92 , \text{kJ/mol} - (-139.3 , \text{kJ/mol}) = 47.3 , \text{kJ/mol}. ] Thus, the value for G at 700 K is 47.3 kJ/mol.
To calculate the heat released when magnesium (Mg) cools from 725 K to 552 K, we use the formula ( q = m \cdot c \cdot \Delta T ), where ( m ) is the mass, ( c ) is the specific heat capacity of magnesium (approximately 1.02 J/g·K), and ( \Delta T ) is the change in temperature. The temperature change ( \Delta T ) is ( 552 , \text{K} - 725 , \text{K} = -173 , \text{K} ). Substituting the values, ( q = 100.0 , \text{g} \cdot 1.02 , \text{J/g·K} \cdot (-173 , \text{K}) ), which calculates to approximately -17656.6 J. Therefore, the heat released is about 17.7 kJ.
K means "okay" KK is also another way of saying it.
To find the pressure of the butane sample, we can use the ideal gas law equation ( PV = nRT ). First, convert the temperature from Celsius to Kelvin: ( 2.0 , \text{C} + 273.15 = 275.15 , \text{K} ). Using the ideal gas constant ( R = 0.0821 , \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} ), we can rearrange the equation to solve for ( P ): [ P = \frac{nRT}{V} = \frac{2.10 , \text{mol} \times 0.0821 , \text{L} \cdot \text{atm} / \text{K} \cdot \text{mol} \times 275.15 , \text{K}}{60.0 , \text{L}} \approx 0.96 , \text{atm}. ] Thus, the pressure of the butane sample is approximately 0.96 atm.