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HNO3 is not used in redox titration because being a good oxidising ageant it oxidises the compound itself whereas HCL is a very volatile and it takes part in the reaction therefore H2SO4 is used in the reaction
Because sulphuric acid is non volatile and its sulphate ion is not interfering during the titration process while HCl is a volatile substance and its chloride ion interfere in the reaction as a reducing agent.
Zn + KNO3 + HCl → ZnCl2 + KCl + NH4Cl + H2O
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It would change your results because concentrated HCl is more acidic then H2SO4, therefore, there would be a larger change in pH quicker.
HNO3 is not used in redox titration because being a good oxidising ageant it oxidises the compound itself whereas HCL is a very volatile and it takes part in the reaction therefore H2SO4 is used in the reaction
Because sulphuric acid is non volatile and its sulphate ion is not interfering during the titration process while HCl is a volatile substance and its chloride ion interfere in the reaction as a reducing agent.
Zn + KNO3 + HCl → ZnCl2 + KCl + NH4Cl + H2O
marri bhi yahi doubt se bhaI DUR KARAN ALE NE 10 Rs E NAAM
It would change your results because concentrated HCl is more acidic then H2SO4, therefore, there would be a larger change in pH quicker.
H2SO4 is a strong acid and will deliver H(+) which will help to proceed the reaction much faster. Thereby, the sulphate-ions barely react in a redoxreaction. If we would take HCl for example, the Cl(-) ions can easily take part in a redoxreaction as a reductor.
Dilute sulfuric acid H2SO4 is an indifferent acid to oxidising substances, while HCl (potential +1.36V) is a reductant and HNO3 (potential +0.96V) is an oxidant.
HCL is used to provide the acidic conditions required in the iodometeric titration.
LiCl+H2SO4=LiHSO4+HCl
Cl- + H2SO4 = (HSO4)- + HCl
hso4- + hcl = H2so4 + cl-
HNO3 should have not been used in redox titration because being a good oxidising ageant it oxidises the compound itself whereas HCL is a very volatile and it takes part in the reaction.