Voltage is like the pressure in your hose pipe. Current is the flow of charge and equivalent to the rate of flow of the water. Due to resistance to the water in the pipe,the pressure of the water will reduce along the length of the pipe but the quantity of litres flowing in the pipe will not change. So voltage will be maximum at the source of the voltage but as you move along the conductor there is voltage drop due to the resistance of the conductor.However, the current is same at all points along the conductor (the flow of charge is uniform at all points)
DC forward voltage is generally related to diodes. It means the voltage across the diode when the diode is forward biased, i.e. when the anode is more positive than the cathode. The forward voltage is the drop across the diode. The amount of drop is a function of current. For typical silicon diodes, the forward voltage drop ranges from 0.6 volts for very small currents, to 1.5 or more volts for large currents.
1.36 volts Ohm's Law: Volts = Amps * Ohms
When the power (energy) is dropped to the value of 50 percent, the decibel loss is 3 dB, but the voltage is dropped to the value of 70.1 percent. Power drop to 50 % means -3 dB; that is 70.1 % voltage drop. Power drop to 25 % means -6 dB; that is 50 % voltage drop.
there is no such thing
A brown out.
How do you calculate voltage drop for starting motor current
A resistor drops both voltage and current, however the term "drop" is generally used to indicate a voltage or current drop across the device, so it is more correctly stated that a resistor drops voltage, by allowing the current in the circuit to decrease.
What is the amount of current flowing through the resistor? Voltage drop is dependent on the current. Ohm x Amps = Voltage drop
The voltage drop depends on the current through the cable.For DC current in cable of 16 mm diameter, at 68° F, the voltage drop is(0.00857) x (current, Amperes) volts.
The correct question is what is the voltage drop across a resistor or the current flowing through the resistor using Ohm's Law where Voltage = Current x Resistance
There are two possible reasons. Firstly, due to the internal resistance of the supply source, there is an internal voltage drop within that source, and this increases as load current increases. In other words, the closed-circuit (load) voltage is always lower than the open-circuit (no-load) voltage. Secondly, a voltage drop always occurs along the conductors between the supply source and the load. Again, the greater the load current, the greater this voltage drop. In a well-designed circuit, these two voltage drops should be insignificant.
Are resistor drops the voltage or current? ANSWER: The voltage DROP is a way to imply that the voltage no matter of the value is what it must be whether it is measured or calculated
Ohm's Law: Voltage = Current times Resistance
cross sectional area of cable * voltage drop
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
A diode has a fixed voltage drop (c), and if the voltage is less than that, no (or very little) current flows. Once the voltage increases above the voltage drop, the current increases exponentially as the voltage increases. A function that models this is: I = exp(b*(V-c)) where V is the voltage, I is the current, c is the voltage drop and b is a parameter that determines how fast the current increases; the value of b varies from one diode to another