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You can find the major axis, 0.5+31.5 or 32 AU. The semimajor axis is half that, 16 AU. Then you can use Keplers 3rd law to calculate the period, which is 161.5 or 64 years.
at least every 4 years, and solar eclipses occur when the sun,moon, and Earth are in a straight line,also in order for the solar eclipse to occur these objects have to be in the order of : SUN1ST MOON2ND AND EARTH 3RD
From Kepler's 3rd law the length of the year at that distance would be 3**(1.5) years, in other words 5.196 years, calculated by taking the square-root of 3-cubed.
It's the 3rd planet from the sun.
A year on Pluto (the time it takes to go around the Sun) is equivalent to 247.92 Earth years. Since its discovery in 1930, Pluto has completed about 1/3 of a complete orbit. This occurs because Pluto is so very far from the sun. In astronomy, the definition of a year is the length of time the Earth takes to revolve about the sun. Measured in Earth days, 1 Pluto year = 90,490.8 Days ---------- It takes 248 Earth-years for Pluto to orbit the sun because pluto orbits at an average distance of 5.9 billion km from the Sun, while Earth only orbits at 150 million km. It takes Pluto 248.09 years to orbit the Sun. (This is about 90,613 Earth days, 8 hours.) 248 years. Since its discovery in 1930, Pluto has only completed a little less than 1/3rd of a complete revolution.
You can find the major axis, 0.5+31.5 or 32 AU. The semimajor axis is half that, 16 AU. Then you can use Keplers 3rd law to calculate the period, which is 161.5 or 64 years.
Using Kepler's 3rd(?) law, the duration of a planet's orbit squared is the same as the planet's distance from the Sun cubed . Jupiter is (on average) 5.2 times further from the Sun than our planet, so we say 5.2 AU(Astronomical Units- distance from Earth to Sun) Using Keplers Law Length of Jovian Orbit Squared = 5.2 cubed (5.2x5.2x5.2) = 140.608 So to get the Jovian Orbital Duration we need the square root of 140.608 Which is 11.858. That's roughly 12 years
this corresponds to Keplers 3rd law of planetary motion P ^2 = R^3 p Squared is equal to the period of revolution, in years r is equal to the distance from the sun in astronomical units. this is a simple version of the principle, Newton modified it.
Assuming you are 11 years old on Earth, you would be about 1/3rd (11 / 29.4) Saturn-years old.
It is the 3rd planet from the sun.
April 27, 4977 B.C. That was when he once calculated that the universe began. Or, you may mean when he published his Laws of Planetary Motion. He published his first 2 laws in 1609 and his 3rd law around 1619.
Yes, Earth is the third planet from the Sun.
3rd
One of the parts of an ellipse is the length of its major axis. Half that is called the semimajor axis. Kepler's 3rd law says that the time to do one orbit is proportional to the 3/2 power of the semimajor axis. IF the semimajor axis is one astronomical unit the period is one year (the Earth). For a planet with a semimajor axis of 4 AUs the period would have to be 8 years, by Kepler-3.
it takes it ten earth years i think but if you are in 3rd grade then you should be learning about the planets by now
The age of the Earth, about 4.6 billion years, isn't really in dispute. Could it be a LOT older, as in billions of years older? No. We know that the Sun and our solar system are at least 3rd generation stars; otherwise there would be no heavy elements in the Earth.
1st Mercury 2nd Venus 3rd Earth