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The rate of chemical reaction can be increased by following ways:- 1. Adding a catalyst. 2. Increasing the temperature of system. 3. Increasing the surface area. 4. Increasing the stirring/mixing rate 5. Increasing the pressure of system (but take care as this is not always the case)
Pressure always decreases with height. This is because atmospheric pressure is just a measure of how much air is weighing down. So the higher you go in the atmosphere, the less air is above you (more of it is below you) and the lower the pressure will be.
More. That is the only answer that is possible with the information provided. The ideal gas law states: PV=nRT. Solving for P gives: P=(nRT)/V. So you can see that if temperature and amount of gas are constant (R is always a constant), decreasing V will increase pressure and increasing V will decrease pressure. An easier formula derived from this one is P1V1=P2V2.
Increasing the temperature of the reaction will always increase the rate, though the actual yield will depend on whether the reaction is exothermic or endothermic. Increasing the pressure of the... Read More
Yes, but those 'negative' catalysts are different compounds then the positives (=increasing rate). They are not that useful, so rather seldom used.
Yes. However the volume of a gas must be constant or decreasing. If the volume is increasing then the pressure may not be increasing. For apex the answer if False.
No. It is not.
raising the temperature of the reactants, by increasing their surface area, by increasing the concentration of reactants, by stirring the reactants, or by adding a catalytic agent can increase reaction rates
The Ideal Gas Law states that PV=nRT, where P=pressure, V=volume, n=number of moles of gas, R=the relativity constant, and T=temp in Kelvin. According to this law, volume (V) varies as V=(nRT)/P. Using this, we can determine that the volume would normally increase with an increase in the number of moles and/or an increase in the temperature and/or a decrease in pressure. Therefore, we can logically determine that the volume of a gas would decrease in the instance of increasing temperature if either the number of moles of gas was decreased or the pressure was increased (to an extent where the level of volume increase by temperature change has been overcome.)
Air pressure is always greater nearer the earth surface than at altitude due to the mass of air above.
The first part of the explanation is understanding why a balloon changes when you put air into it. Before you blow up a balloon, you can see that the volume is small and that the balloon is elastic. As you put more air into the balloon you are increasing the pressure. The air is packed in tight, so it attempts to push out and escape, so the balloon's surface stretches until a balance is reached. The tension of the balloon's surface combined with the outside atmosphere's pressure matches the internal pressure of the air. This equilibrium is always held. If you increase the pressure (putting more air into the balloon) the balloon's surface gives just enough so that you equilibrium is reached again. It is this maintaining of equilibrium that answers your question. If you try and decrease the volume in one area of the balloon, the air is going to push out another area of the balloon to make up for the lost volume. The volume is always maintained and the pressure remains constant.
The first part of the explanation is understanding why a balloon changes when you put air into it. Before you blow up a balloon, you can see that the volume is small and that the balloon is elastic. As you put more air into the balloon you are increasing the pressure. The air is packed in tight, so it attempts to push out and escape, so the balloon's surface stretches until a balance is reached. The tension of the balloon's surface combined with the outside atmosphere's pressure matches the internal pressure of the air. This equilibrium is always held. If you increase the pressure (putting more air into the balloon) the balloon's surface gives just enough so that you equilibrium is reached again. It is this maintaining of equilibrium that answers your question. If you try and decrease the volume in one area of the balloon, the air is going to push out another area of the balloon to make up for the lost volume. The volume is always maintained and the pressure remains constant.
The rate of chemical reaction can be increased by following ways:- 1. Adding a catalyst. 2. Increasing the temperature of system. 3. Increasing the surface area. 4. Increasing the stirring/mixing rate 5. Increasing the pressure of system (but take care as this is not always the case)
Air always flows towards areas of low pressure - and away from high pressure.
Pressure always decreases with height. This is because atmospheric pressure is just a measure of how much air is weighing down. So the higher you go in the atmosphere, the less air is above you (more of it is below you) and the lower the pressure will be.
The pressure increases as the object goes deeper into the fluid; the pressure is always perpendicular to the surface of the object
More. That is the only answer that is possible with the information provided. The ideal gas law states: PV=nRT. Solving for P gives: P=(nRT)/V. So you can see that if temperature and amount of gas are constant (R is always a constant), decreasing V will increase pressure and increasing V will decrease pressure. An easier formula derived from this one is P1V1=P2V2.