Boron has an electronic configuration of 1s22s22p1 (it has 5 electrons). In order to reach the stable electron configuration of a noble gas with a completely filled valence shell, boron atom has to lose 3 electrons to obtain a stable duplet structure (i.e. 2 electrons in its first electron shell). After losing 3 electrons, the boron atom forms a B3+ ion, or a so-called tripositive ion.
Mo^3+ = [Kr] 4d^3
the chemical symbol for boron ion is B+++
boron ion is represented as B+, singly charged, positive.
Boron has 5 protons.
3
Boron electronic configuration is 1s22s22p1 so three electons in the outer energy level so it easily loss the three electrons it become tripositive ion
Mo^3+ = [Kr] 4d^3
the chemical symbol for boron ion is B+++
Boron is an element.
the chemical symbol for boron ion is B+++
There are many factors when it comes to Boron. If it were to form an Ion, then it would drop a total of three electrons.
boron ion is represented as B+, singly charged, positive.
Boron has 5 protons.
It fizzes
Br2+
3
It is a positive ion. Its' charge is 3+.