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Boron has an electronic configuration of 1s22s22p1 (it has 5 electrons). In order to reach the stable electron configuration of a noble gas with a completely filled valence shell, boron atom has to lose 3 electrons to obtain a stable duplet structure (i.e. 2 electrons in its first electron shell). After losing 3 electrons, the boron atom forms a B3+ ion, or a so-called tripositive ion.

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Q: Why does boron form a tripositive ion?
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