0
Why does intensity decreases as the distance from the light source increases?
Wiki User
∙ 9y agoWant this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
Why intensity decreases as distance from the light source increase?
intensity increases as distance decreases. you cant explain that. scources- bill o'reily
Which wave property decreases as you get farther away from the source of a sound?
Intensity
How does distance affect intensity of radiation?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
How does light intensity vary with distance form the source?
Light intensity is inversely proportional to the square of the distance: I = k/d2
What happens to the intensity of ionizing radiation when you move away?
The intensity reduces in proportion to the square of your distance from the source.
Why intensity decreases as distance from the light source increase?
intensity increases as distance decreases. you cant explain that. scources- bill o'reily
Which wave property decreases as you get farther away from the source of a sound?
Intensity
How does distance affect intensity of radiation?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
How does the intensity of a sound wave change if the distance from the source increases by a factor of 2?
The intensity increases by a factor of 4-APEX
Why does the intensity decrease with the square of the distance from a point source?
Intensity is defined as energy per unit area. As we move away from the point source, the area over which the energy distributes is generally spherical or hemispherical. The area of a sphere or hemisphere increases proportional to the square of radius, where the radius in this case is the distance from the point source. Thus Intensity, which is inversely proportional to area, decreases with the square of distance. Hope it was clear. Visit MechMinds.ca for any further help!
Why does moving away from a radio affect the loudness you hear?
because sound waves spread out, intensity decreases with distance from the source.
How does the intensity of a sound wave change if the distance from the source is reduced by a factor of 4?
- 6 dB is incorrect. It will decrease by 12 dB.
Why does the intensity of a sound decrease as the distance from the source increases?
the waves spread out over a larger areathe waves are absorbed by the medium as they pass through itthe waves are being scattered by irregularities in the medium and don't all proceed forwardetc.
What distance increase is needed to reduce a sound's intensity from an initial 100dB to a final 80dB?
Sound intensity is inversely proportional to the square of the distancefrom the source.-- Increase the distance from the source by 10 times.-- Sound intensity decreases to 1/102 = 1/100 .-- 10 log ( 1/100 ) = -20 dB-- 100 dB - 20 dB = 80 dB
What is the maximum distance at which the riveter is still audible?
The intensity of a sound produced by a point source decreases as the square of the distance from the source. Consider a riveter as a point source of sound and assume that the intensities listed in Table 12.1 are measured at a distance 1 m away from the source. What is the maximum distance at which the riveter is still audible? (Neglect losses due to energy absorption in the air.)
Decibels in ear?
Never forget to tell the distance of the measuring microphone (at the place of your ear), from the the sound source because the closer you are to the sound source the louder it will be.The sound pressure level decreases by 6 decibels per doubling of distance from the source to 1/2 (50 %) of the sound pressure initial value.The sound pressure decreases inversely as the distance increases with 1/r from the sound source.
What happens to the illuminance when you move away from the light source?
The intensity decreases.
