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Benedict test have a negative result in glycogen because glycogen is a polysaccharide. Benedict test is meant for testing reducing sugars. It can also give positive results in the case of disaccharide or monosaccharide.

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15y ago
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14y ago

Because it is a so-called nonreducing sugar in neutral or alkaline solution.

In acidic solution however (e.g. in sugar containing limonades),

the nonreducing di-saccharide sucrose is quit easily turned ('hydrolysed' or split) into

the two mono- saccharides glucose and fructose, which are in fact (in this test) reducing.

  • The aldose glucose is a straight forward reducing sugar, so positively detected by B's test reagent.
  • The ketose fructose is not strictly a reducingsugar (it is an beta-hydroxy-ketone, not an aldehyde), but it becomes reducing thus giving a positive test.

    This is because this 'alpha-hydroxy-ketone' is converted to the aldoses: glucose and mannose, by the alkaline solution of the Benedict's test (called 'keto-enol'-tautomerisation).

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15y ago

sucrose is a glucose polymer that doesn't have the free carbonly group to react with the benedicts solution.

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14y ago

Benedict's Reagent tests only for 'reducing sugars' (monosaccharides), starch is a polysaccharide

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12y ago

Benedict's solution reacts with simple sugars like glucose, which are monosaccharides. Sucrose is not a simple sugar, it is a disaccharide.

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15y ago

solution remain blue

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Q: Why does starch produce a negative result with Benedict's reagent?
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Related questions

Does using benedicts reagent on honey produce a positive result?

yes


Will hydrolysed dextrine give positive response to Benedict test?

Yes, it should. Benedicts test will be positive for reducing sugars, and since glucose is such a sugar, and would be a product of dextrin hydrolysis, you should get a positive result with Benedicts reagent.


When glycogen is added to benedicts reagent why would it remains blue?

Although glycogen is a carbohydrate, it is classified under POLYSACCHARIDES which are non-reducing sugars. Benedict's reagent is used to test for the presence of non-reducing sugars. The positive result for this is a brick-red precipitate or solution. It remained blue (which is negative) due to fact that ALL POLYSACCHARIDES (such as glycogen) ARE NON-REDUCING SUGARS > I'm a Nursing Student. >M.J.T.M.E.


An unknown sample is tested with both biuret reagent and benedicts reagent both test result in a blue color what has been learned and why are these called negative results?

That the unknown sample is not a monosaccharide and is does not contain peptide bonds (is not a protein). This is because they both produced negative results because Biuret tests positive in solutions that contain peptide bonds and will turn a violet color. Benedict reagent reacts to monosaccharides and will turn green-reddish orange when a monosaccharide is present. Neither of these things happened so the results are negative.


What would the result of crackers in benedicts test?

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2-Methyl-1-propanol is a primary alcohol and so will not react with Lucas reagent at room temperature.Cyclopentanol is a secondary alcohol and so will react with Lucas reagent in 3-5 minutes (solution turns cloudy). Cyclopentyl chloride is the result.1-Methylcyclopentanol is a tertiary alcohol and so will react immediately with Lucas reagent to produce turbidity. 1-Chloro-1-methylcyclopentanol is the result.


Why does sucrose not react to Benedicts when glucose and fructose its components do?

Fructose and glucose are joined by their glycosidic bond in such a way as to prevent the glucose isomerizing to aldehyde, or the fructose to alpha-hydroxy-ketone form. This stops it reacting to Benidict's reagent. However sucrose indirectly produces a positive result with Benedict's reagent if heated with dilute hydrochloric acid prior to the test, although after this treatment it is no longer sucrose. ;-)


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Iodine-KI reagent. Add to the substance being tested directly. Result: If positive, Turns Blue/Black If negative, (absence of starch) Solution remains orange/yellow.


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The solution must by homogeneous.


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