A: absolutely not lamps needs current a long cord introduce IXR drop making less current for the lamp to use it
A: Because both item are connected is series. Any resistance connected in series will carry the same current no matter of the resistance value or the number of resistors. However for an incandescence lamp the value will change when turn on and change when it is hot, That is because lamps have different property then resistance when cold and hot
Current = Voltage/Resistance Current = 18/10 = 1.8 A
Assuming you are referring to house lamps, these are always connected in parallel with each other. Each lamp will draw a current, the value of which depends on the wattage of the lamps. As each lamp is added, the supply current will increase by the amount of current drawn by that lamp.
A: The current is not a function of voltage available but rather the power needed to light the lamp. To answer your question a 100 watts lamp will require 1.83 times more current for a lamp rated as 100 watts at 120 volts.It is a basic ratio 220:120AnswerI disagree with the previous answer. The power rating of a lamp only applies when the lamp is subject to its rated voltage -which is why both values are shown on the lamp (e.g. 60 W / 120 V).So, if you subject a lamp to less than its rated voltage, it will not achieve its rated power. In fact, the decrease in power will be significantly greater than the corresponding decease in voltage. It will certainly not 'compensate' by drawing more current!However, to directly answer your question, the current drawn by a lamp connected to a 220-V supply will indeed be greater than the current drawn by the same lamp connected to a 110-V supply.
It will if the batteries are connected in series. If they are connected in parallel, the lamp will burn longer, but not brighter.
I = E/R
The formula you are looking for is R = E/I. Resistance is stated in ohms.
Since power is volts time amps, the current in a 60W lamp connected to 120V is 0.5A. Since a lamp is a resistive load, there is no need to consider power factor and phase angle, so that simplifies the explanation. ======================== Assuming this is an incandescent or halogen lamp (using a filament to make the light) there is a trick here: the resistance of a lamp filament varies with temperature and does not follow Ohm's law. The resistance will be much lower, thus the current will be much higher when the filament is cold, when the lamp is first connected. As the filament heats up, the resistance increases until it gets to a steady operating point of 0.5A. For a halogen lamp, the operating temperature is about 2800-3400K, so the R at room temperature is about 16 times lower than when hot... so when connected, the current is about 8A but drops rapidly. The current could be even higher if the lamp is in a cold environment. Non-halogen lamps operate at a lower temperature and would have a lower initial current--about 5A. And this all assumes the lamp is rated for 120V. If it is a 12V/60W lamp, the filament will probably break and create an arc, which may draw a very large current.
For current to flow through the lamp, there must be a potential difference (voltage) applied across opposite ends of that lamp.
A capacitor is connected across the lamp's choke (inductor) in order to improve the power factor of the lamp. Too low a power factor will result in the lamp drawing more load current than is necessary -'improving' the power factor, raises its value, and reduces the load current.
i guess P=VI ,so I= 100/120=.83 A
In a series circuit there is only one path for current to flow. The current will flow through each good lamp. If any lamp opens (blows), then the circuit is broken and current flow stops. The older strings of Christmas tree lights used to be connected in series and it was hard to fine the blown bulb. If there were two burnt out bulbs almost impossible to find.
When two light bulbs are connected in series , there is voltage drop which causes the second lamp to dimAnswerWhen two lamps are connected in series, neither lamp will be subject to its rated voltage and, so, each lamp will be dim. Surprisingly, perhaps, the lamp with the higher power will be dimmer than the lamp with the lower power!
It can be either.
WE know v=IR ,the bulb have resistance which will be added and decrease the current as above formula (Volatage constant)AnswerIt depends how they are connected. If they are connected in parallel, then each lamp will be operating at its rated power and will draw its rated current -assuming the lamps are identical, then the supply current will be four times larger than the current drawn by any one of the lamps (their combined resistance will be one-quarter of their individual resistance).On the other hand, if they are connected in series, then their resistances are additive and the resulting current falls as each lamp is added to the circuit. And, as none of the lamps is subject to its rated current, none of them will operate at their rated power.
A lava lamp is a chemical change
The lamp with a thick filament will draw more current than a lamp with a thin filament. Thick filament has more surface area to excite and release electrons, so it will require more current.
The idea is to use Ohm's Law (V=IR). In this case, the relevant voltage is the 10.2 V across the lamp.
a mood lamp is a lamp that can change a mood in a room
a lava lamp is a chemical change because it is.
A lamp or light fitting will light up if connected to either Alternating Current (AC), or Direct Current (DC). AC is from the mains, and DC is from a battery. So it depends on the construction and components used to construct the lamp as to which electrical source you use.
Which brake lamp are you needing to change? Brake/turn signal lamp.