i=incidence angle, r=angle of refraction
Refractive index= sini/sinr
Since for different materials value of refractive index is different hence both angles are not equal.
nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees
This is total internal reflection where the angle of refraction is 90 degrees and its incident angle would be the critical angle(angle of incident for which the angle of refraction is 90).... This hapens when the angle of incidence is in a medium more dense than the angle of refraction's medium
The second angle of incidence is equal to the angle of refractions.
You mean that as light is incident normally. Here the angle of incidence will be 0. As per Snell's law sine of angle of incidence / sine of angle of refraction = refractive index So Sin i = mu * sin r As i=0 then r too has to be 0 as mu is not equal to 0 Hence no refraction becomes possible for a normally incident light ray
when the angle of refraction is zero you still need an angle of incidence because it still reflects back.
nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees
No.
This is total internal reflection where the angle of refraction is 90 degrees and its incident angle would be the critical angle(angle of incident for which the angle of refraction is 90).... This hapens when the angle of incidence is in a medium more dense than the angle of refraction's medium
The second angle of incidence is equal to the angle of refractions.
terms realated to refraction of light are * interface * incident ray * refracted ray * point of incidence *normal *angle of incidence * angle of refraction *angle of deviation
Usually not.
The law of reflection states that the angle of incidence is equal to the angle of REFLECTION. Refraction is an entirely different phenomenon and has its own law.
The angle of incidence
Not exactly, the angle of refraction = the angle of incidence, which means the ratio of sine of angle of incidence to the sine of angle of refraction is constant for two media. That is sin i /sin r = constant , and this constant is called refractive index
You mean that as light is incident normally. Here the angle of incidence will be 0. As per Snell's law sine of angle of incidence / sine of angle of refraction = refractive index So Sin i = mu * sin r As i=0 then r too has to be 0 as mu is not equal to 0 Hence no refraction becomes possible for a normally incident light ray
angle of incidence of a wave hitting a surface equal the eagle of refraction.
when the angle of refraction is zero you still need an angle of incidence because it still reflects back.