Because of water's nature to partially ionise itslef into hydronium and hydroxide ions, any solution of either a hydroxide or an acid will always be affected by this tendency, making the actual concentrations differ slightly from the expected ones.
It is a physical change. The sodium hydroxide dissolves, but it is still sodium hydroxide.
When sodium hydroxide dissolves in water, it undergoes a physical change as the sodium hydroxide molecules split apart into ions, which are then surrounded by water molecules. This process does not involve a change in the chemical composition of the sodium hydroxide molecule itself.
It is a physical change because no new substances are formed during the process of dissolving. Sodium hydroxide dissociates into its ions in water, but the chemical composition of the sodium hydroxide remains the same.
The chemical name is Sodium Hydroxide. It is made of Na+ ions and OH- ions.
When sodium hydroxide dissolves in water, it undergoes an exothermic reaction, releasing heat. If the amount of sodium hydroxide is doubled, the same amount of heat will be released, resulting in an increase in temperature. The specific temperature change would depend on the initial amounts and concentrations of the sodium hydroxide and water.
The reaction between iron (III) chloride and sodium hydroxide is a chemical change as new substances are formed. Iron (III) hydroxide and sodium chloride are produced as a result of the reaction.
To determine the normality of HCl (hydrochloric acid), you can perform a titration experiment with a standardized solution of sodium hydroxide (NaOH) of known concentration. By recording the volume of NaOH required to neutralize the HCl, you can calculate the normality of the acid using the formula: Normality = (Molarity of NaOH) x (Volume of NaOH used) / Volume of HCl sample.
The dissolving of sodium hydroxide in water is a physical change because no new substances are formed. Sodium hydroxide breaks down into its ions in the water, but its chemical composition remains the same.
The reaction between copper sulfate and sodium hydroxide is a chemical change, as new substances are formed with different chemical properties from the original substances. The blue copper sulfate solution reacts with the colorless sodium hydroxide solution to form a blue precipitate of copper hydroxide and sodium sulfate solution.
Dissolving sodium hydroxide in water is considered a physical change because it involves breaking down the solid sodium hydroxide into individual ions without changing the chemical composition of the substance. The process is reversible, and the resulting solution can be separated to recover the original components.
When copper sulfate is added to sodium hydroxide, a blue precipitate of copper hydroxide is formed. The color change observed is from the initial blue color of copper sulfate to the blue precipitate of copper hydroxide.
To calculate the normality of ammonium hydroxide (NH4OH), we need to know the molarity first. Once we have the molarity, we can determine the normality for NH4OH by accounting for the number of equivalents it can provide in a reaction. Normality is calculated as the molarity multiplied by the number of equivalents per molecule.