The resistance of a piece of wire changes with temperature. In a filament bulb the wire is heated to about 3000 degrees C so a large change in resistance can be expected.
A 240 v 105 w halogen bulb has a cold resistance of 35 ohms, but when running its resistance is 549 ohms.
It will affect the current because of the resistance that's increasing through the flow.
The filament of a light bulb overs enough resistance to current flow, that the filament heats up so much that it will glow and produce visible light.
Yes, a light bulb is a source of light. When current is going through the filament the resistance generates enough heat that the filament glows, producing light.
600w - the thicker filament has a lower resistance, which leads to a higher current and thus higher wattage
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
If you are talking about an incandescent light bulb then its called a filament. It is thin so that it has a high level of resistance. Current going through the filament causes it to heat up and give off EM radiation in the spectrum of visible light.
An incandescent bulb has a filament that has a resistance. The value of the resistance determines the current that will flow for a given supply voltage. The heat generated by the current flowing through the filament gives off light. As the resistance of the filament decreases the current increases and you get more light.
A low resistance bulb has a thicker filament.
The incandescent light bulb. The tungsten filament lights due to it's resistance of the current flowing through it.
The filament of a light bulb overs enough resistance to current flow, that the filament heats up so much that it will glow and produce visible light.
The resistance of the filament in a light bulb is(voltage at which the bulb is designed to operate)2/(the rated power/watts of the bulb)
Yes, a light bulb is a source of light. When current is going through the filament the resistance generates enough heat that the filament glows, producing light.
The filament is a special metal composition of tungsten that conducts current and heats up and emits light as a result of the current and its internal resistance.
An incandescent light bulb is essentially a wire through which current flows. The wire gets heated up and glows giving off light. According to Ohm's Law Volts = Current x Resistance. In this case resistance is the resistance of the filament. Since in a residence the voltage remains more or less constant, the way more energy would be use is if more current passed through the filament. If the resistance of the filament decreased then the current would increase. Not sure how an aging bulb would have a decreased resistance. If this were somehow possible such that the composition of the filament changes and reduced resistance then the energy required to operate the bulb would increase.
The filament in the bulb has resistance. The current flowing through the resistance of bulb causes the filament to dissipate energy in the form of heat and light. The filament is actually glowing white-hot because of the energy it is dissipating, thus giving off light.
600w - the thicker filament has a lower resistance, which leads to a higher current and thus higher wattage
The equation that you are looking for is I = E/R. Amps = Voltage/Resistance in ohms.
A light bulb works by passing an electric current through the filament, which is usually made from a high resistance substance such as tungsten. When the current flows through, the filament glows which produces the light. When it burns out, no electricity passes and no glowing occurs. Source: i just know