The answer comes from Energy Conservation Principle which commonly is known as Kirchoff's Voltage Law.
Voltage is basically work done per unit charge and work is form of energy which has to be conserved. Also, electric fields are conservative that means work done depends only on initial and final points.
Combining all that I have said, if you make your starting and end point same, that is run in a loop, effectively work done will be zero (Potential difference is zero). Thus in a parallel circuit if the voltages are not equal, changing the loops will violate this principle.
Let's say you have 2 resistors in parallel attached to a battery. If you assume that the voltages of branches are different, then considering the loop that contains both the resistors and applying KVL violates energy conservation and that's not possible. Thus the only possibility is the voltage has to be same.
Additional Note: The same voltage might not be equal to battery voltage if there is any resistor in path of parallel wires and battery. But the parallel voltages will be equal.
In a parallel circuit, each component has its own separate path for current to flow. Because of this, the voltage across each component remains constant, as the voltage source provides a consistent potential difference to each branch. Therefore, the voltage across each component in a parallel circuit remains the same.
The current (amps) will remain constant, but the voltage will drop.
P=VI If current (I) increases then P will increase proportionally. That is, assuming that voltage (V) remains constant. If voltage decreases and current increases or vice versa, proportionally then P will remain the same.
Parallel branches each draw a current from the supply. The more branches, the more current is drawn. Adding additional loads to a series circuit increases its resistance, causing its supply current to reduce.
Tree lights have parallel circuits because the rest of the lights will remain on if one goes out. Imagine trying to find the one bad bulb on a string of lights if one were to go out. This way, only one light goes out, so it can easily be found and replaced. Hope this helps!
1. You may not want all lights on, so with a parallel circuit you can turn some off while the others remain lit (you cannot do this with series) 2. If one of the lights go out, the others will remain lit
The rest of the lights in the system will remain illuminated. Except in that branch of the circuit. The parallel branch(s) get more current if the voltage potential remains the same.
If the voltage between the ends of a series circuit changes, the current in thecircuit definitely does not remain constant. The current does change by the samefactor as the voltage.The current at every point in the series circuit is the same current.
The voltage across the resistors will remain constant.
Since resistance is the ratio of voltage to current, we can say that halving the resistance will result in twice the current.
Kirchoff's voltage law states that the signed sums of the voltage drops in a series circuit add up to zero.Kirchoff's current law states that the current everywhere in a series circuit is the same, more specifically, that the signed sums of the currents entering a node is zero.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
In a parallel circuit each bulb has the same voltage applied so if one bulbfails all the others will remain lit.
A: assuming a infinite current source the current will increase accordingly
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source.
A: The relationship is that the current will divide for each paths in a parallel circuit and the voltage drop across each will be the source voltage. In a series circuit the current will remain the same for each component but the voltage will divide to reflect each different component value. And the sum of all of the voltage drops will add to the voltage source.
A: No matter how many resistor of different value are inserted the current will remain the same for each. The voltage drop will vary with the difference in resistors and i a parallel path is found along the way the current will divide according to the resistors values