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The mass of the Earth is 5.97x1024kg, which is significantly greater than that of any one individual.
Now let's say that you weigh 60kg and you are a perfect sphere with a diameter of 1m. To calculate the gravitational force that your body exerts, you can use the following equation:
Where:
G is the gravitational constant (6.67300 × 10-11 m3 kg-1 s-2)g is the gravitational force
m is your mass
r is your radius
To calculate:
g = [6.67300 × 10-11 m3 kg-1 s-2] x [60kg / (1m)2]
g = 4.002x10-9 m/s2
Earth, in comparison, has a gravitational force of 9.81m/s2 - which is 2,451,274,360× more than the gravitational pull of you. Thus: when you jump up into the air, you will be pulled back onto the Earth's surface, and the Earth will not fall towards you.
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It does. When you jump, both you and the Earth move apart, and then fall back together. For every action, there is an equal and opposite reaction. After the jump, the equation m(person)*v(person) = - m(earth)*v(earth). A typical person weights 70 kg, and the Earth weighs approximately 6,000,000,000,000,000,000,000,000 kg. So to make the equation equal, the velocity of the Earth is about 1/85000000000000000000000 as much as the velocity of the person. This is really too small to notice by any current means of measurement.
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