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If you have an infinite sheet of charge, it is all you can see, in that direction. If it is (let us say) in front of you, then that is all you can see to the front, it has no visible edge, you can see nothing on the other side of it (you could see something in front of it, but that is beyond the parameters of the stated problem). No matter how close or how far away you may be, it looks exactly the same. It will never look any smaller as it recedes into the distance, unlike finite objects. Vision is also a form of electromagnetism. If we were talking about light emission, the amount of light you would receive from an infinite glowing sheet would always be the same, at any distance. So any other electromagnetic effect will work the same way.

Technically, what is happening is that as you move farther away, you get less field from the closer parts of the infinite sheet, but you are also exposed to more of the sheet, in exactly the same proportion.

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Q: Why field is independent of distance from infinite sheet of charge?
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What is the effect of a magnetic field on a stationary electric field?

The magnetic field will have no effect on a stationary electric charge. ( this means that the magnetic field is also stationary. ) If the charge is moving , relative to the magnetic field then there might be an effect, but the size and direction of the effect will depend on the direction of the electric charge as it moves through the field. If the charge is moving parallel to the field there will be no effect on it. If the charge is moving at right angles to the field then it will experience a force that is mutually orthogonal to the field and direction of the motion. You really need diagrams to properly explain this


What makes a electric field?

The presence of charge creates an electric field. The electric field is just a convenient quantity of how much another charge would move *if* it were placed near the first charge.


Describe an electric field?

The electric field is defined as the force per unit positive charge that would be experienced by a stationary point charge at a given location in the field.


A negatively charged object is placed within a positive electric field. what happens to the object?

Electric Field between positive and negative charges. If the Electric Field in which both the positive and negative charges are present is stronger than the Electric Field between the two charges we are talking about, the the negative charge will move away from the positive charge in that positive direction of the field. If not, then the negative charge will get attracted to the positive charge and stay at the position of the positive charge. It will be pulled toward the source of the electric field. (Novanet)


Why a stationary charge do not feel any force in magnetic field?

we know that force on a charge in magnetic field F=qvbsinx q-charge v-velocity b-strenth 0f magnetic field x-angle between the motion of chage and the magnetic field as the charge is stationary so v=0 so,F=0 so charge donot fill any force on it.

Related questions

Why is the electric field of an infinite charged sheet not infinite?

This is a matter of limits. If you are measuring the electric field at a point that is a distance off of an infinite sheet of charge the direction of the electric field will be perpendicular to the sheet due to the symmetry of the situation. We can think of the radius as the distance between a point on the sheet and the normal line to the sheet that passes through the point where the electric field is being considered. If we look at the addition to the electric field from the charge on the sheet as this radius approaches infinity the component of the electric field in the direction of the net electric field will approach 0.P.S. Drawing a diagram of the situation with arrows denoting the directions of force from different parts of the sheet can be very helpful in understanding.


The strength of an electric field depends on the what?

The amount of charge that produces the field and on the distance from the charge. (Novanet)


If you have two particles of charge 3q and -q along the x axis how can you mathematically demonstrate the zero electric field point past the -q charge?

objects with charges and q and 3q are placed on a lineBesides an infinite distance away from the charges, where else can the electric field possibly be zero


Which of the following is true about the electric field around an electric charge?

The electric field around an electric charge varies inversely as the square of the distance to the charge.


Circle the letters of the factors that the strength of an electric field depends on.?

The strength of an electric field depends on the charge that causes it, and on the distance from the charge.


What happens to the electric field when you get farther from an electric charge?

An electric field gets stronger the closer you get to a charge exerting that field. Distance and field strength are inversely proportional. When distance is increased, field strength decreases. The opposite is true as well. Additionally, field strength varies as the inverse square of the distance between the charge and the observer. Double the distance and you will find that there is 1/22 or 1/4th the electric field strength as there was at the start of your experiment.


The strength of an electric field depends on the?

Electric field strength depends on direction and magnitude because it is a vector quantity.


What is a strong electric field?

THE MAGNITUDE OF ELECTRIC FIELD IS kq/radius-square . IF THE Q[THAT IS CHARGE ] IS BIGGER IN MAGNITUDE OR IF THE DISTANCE BETWEEN THE CHARGE PARTICLE AND POINT CHARGE IS MINIMUM THAN WE CAN SAY THAT IT IS A STRONG ELECTRIC FIELD


What is the Difference between line charge density and surface charge density?

The electric field of an infinite line charge with a uniform linear charge density can be obtained by a using Gauss' law. Considering a Gaussian surface in the form of a cylinder at radius r, the electric field has the same magnitude at every point of the cylinder and is directed outward. The electric flux is then just the electric field times the area of the cylinder.


Where is an electric field the strongest?

Near the poles, weakest at the midpoint between them


How can the electrical potential energy of a charged particle in an electric field be increased?

THIS IS A GOOD QUESTION IF WE PLACE THE CHARGE IN THE ELECTRIC FIELD AT A DISTANCE R FROM THE ELECTRIC FIELD AND PLACED THE ANOTHER POINT CHARGE AT A ANOTHER DISTANCE r WHERE R IS GRATER THAN THE SMALL R THEN THE ELECTRIC FIELD AT r IS MORE THAN THE ELECTRIC FIELD AT POINT R.ORWE CAN SAY THAT IF THE CHARGE IS PLACED IN THE DIRECTION OF ELECTRIC FIELD THAN ITS ELECTROSTATIC POTENTIAL ENERGY WILL DECREASE OR WHEN IN DIRECTION OPPOSITE THAN VICEVERSA


What is the electric field due to a long line charge?

Here we have to think a little bit. When there is a point charge then the field at a given point at a distance r from the charge say q coulomb will be 9 x 10^9 q / r^2 V /m But if the charge is distributed over a lengthy wire uniformly then the field at a given point could be found by integration technique or by applying Gauss law. Hence the field due to a line charge of linear charge density K, the field at a point at distance r from the line will be 18 x 10^9 K / r. To derive the above expression will be an interesting one which is to be enjoyed by knowing and doing so. Really Mathematics is the queen of science.