Line voltage has increased because more power can be transported at higher voltages with less I^2*R losses (loss due to the line resistance). This is why systems originally designed for 110kV may have had minor upgrades to 115kV, and are often run near 1.04% of this (120-121kV) most of the time. This allows more power to be transported with minimal investment.
The voltage drop in a line can be decreased by
The energy supplied by a power line is determined by its load, not by its voltage. For a given energy demand by its load, the higher the liine's voltage, the lower the resulting load current.
To find the line voltage at the panel, you need to add the voltage loss to the voltage at the receptacle. Since the receptacle has 110 V and there is a voltage loss of 6 V, the line voltage at the panel is 110 V + 6 V = 116 V.
its because of transformers . they work with pulse
Because power is power. If you maintain the same power, while increasing the voltage, you must decrease current. P=IE.
Line-to-line voltage in a three-phase system is calculated using the formula ( V_{LL} = \sqrt{3} \times V_{LN} ), where ( V_{LN} ) is the line-to-neutral voltage. This relationship arises because the line-to-line voltage represents the voltage difference between two phases, while the line-to-neutral voltage is the voltage from a phase to the neutral point. If you have the line-to-line voltages directly measured, you can also use the voltage differences between any two phases to determine the line-to-line voltage.
A voltage is applied to a signal line. The voltage of the line changes gradually from 0 to +V. The "edge speed" is the rate of change of voltage of the line. A voltage is applied to a signal line. The voltage of the line changes gradually from 0 to +V. The "edge speed" is the rate of change of voltage of the line.
The term, 'unbalanced system' refers to an unbalanced load. Under normal circumstances, an unbalanced load leads to unbalanced line currents. The line voltages are determined by the supply and remain symmetrical, even when the load is unbalanced. As your question refers to a 'line to neutral' voltage (i.e. a phase voltage), you must be referring to a star (wye) connected load, in which case the phase voltage (line to neutral voltage) is 0.577 (the reciprocal of the square-root of 3) times the line voltage (line to line voltage).
The line voltage increased over 110% of it's normal level is known as Surge , Whereas the surge monitor is a device which is used to measure the voltage increase than the normal value.
To convert a 440V line voltage to phase voltage in a three-phase system, you divide the line voltage by the square root of 3 (approximately 1.732). This means the phase voltage is calculated as ( V_{phase} = \frac{V_{line}}{\sqrt{3}} ). For 440V line voltage, the phase voltage would be approximately 254V.
Phase, if you are referring to line, as power line from pole.
the voltage between 1 line & phase =120v The voltage between 2 line =240