It would be very difficult and expensive to add any more faces to Mt. Rushmore.
It would also be politically difficult to get authorization for the project even if the money and a sculptor could be found.
Do it ur selve dummy This was written by Claire Raddant
In Java:int[] myArray;// or: int myArray[]followed by:myArray = new int[16];Instead of int, you can use any other data type, including a class.
public int sum(int[] x) {int sum = 0;for(int i : x) {sum += i;}return sum;}public int average(int[] x) {// Note that this returns an int, truncating any decimalreturn sum(x) / x.length;}
// return the larger of any 2 numbers int larger (int a, int b) { return a>b?a:b; } // return the largest of any 3 numbers int largest (int a, int b, int c) { return larger (larger (a, b), c)); } // return the middle value of any 3 numbers int middle (int a, int b, int c) { if (a>b) a^=b^=a^=b; // swap a and b (b is now the larger of the two) if (b>c) b^=c^=b^=c; // swap b and c (c is now the largest of all three) return larger (a, b); // return the larger of a and b }
int n1; int n2; int n3; int n4; int n5; int n6; int n7; int n8; int n9; int n10; int n11; int n12; int n13; int n14; int n15; int n16; int n17; int n18; int n19; int n20; int n21; int n22; int n23; int n24; int n25; int n26; int n27; int n28; int n29; int n30;
int smallest_positive(int a, int b, int c) { int s = 0; while (a && b && c) { s++; a--; b--; c--; } return s; // works only for positive integers } int smallest(int a, int b, int c) { int test = INT_MIN; while ((a-test) && (b-test) && (c-test)) test++; return test; }
Yes, it is int.
#include<iostream> void insertion_sort(int* a,int len) { for(int i=1; i<len; ++i) { int* hole=a+i; int* prev=hole-1; int cur=*hole; while(hole!=a && cur<*(prev)) { *(hole)=*(prev); --hole, --prev; } *hole=cur; } } void print_array(int* a,int len) { for(int i=0; i<len; ++i) std::cout<<a[i]<<" "; std::cout<<std::endl; } int main() { int a[]={9,1,8,3,7,2,5,4,6}; int size=sizeof(a)/sizeof(a[0]); std::cout<<"Before:\t"; print_array(a,size); insertion_sort(a,size); std::cout<<"After:\t"; print_array(a,size); return(0); }
You can do this by returning it just like any other data type. int[] f() { return new int[0]; }
// declare a function int* function(int, int); or int* (function)(int, int); // declare a pointer to a function int* (*pointer_to_function)(int, int);
She int dating any one A hobbit.
Int.,Float.Double,Character