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Why intensity decreases as distance from the light source increase?
Wiki User
∙ 9y ago
intensity increases as distance decreases.
you cant explain that.
scources- bill o'reily
Lesly Jaskolski
Wiki User
∙ 13y agoThis follows from the Law of Conservation of Energy. The same amount of energy gets dispersed over a larger area.
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How does distance affect intensity of radiation?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
By how many times must the distance from a point source be increased to reduce the sound intensity by half?
Increase the distance by 70.7% . To 1.707 times the original distance.
Which wave property decreases as you get farther away from the source of a sound?
Intensity
How does light intensity vary with distance form the source?
Light intensity is inversely proportional to the square of the distance: I = k/d2
What happens to the intensity of ionizing radiation when you move away?
The intensity reduces in proportion to the square of your distance from the source.
What distance increase is needed to reduce a sound's intensity from an initial 100dB to a final 80dB?
Sound intensity is inversely proportional to the square of the distancefrom the source.-- Increase the distance from the source by 10 times.-- Sound intensity decreases to 1/102 = 1/100 .-- 10 log ( 1/100 ) = -20 dB-- 100 dB - 20 dB = 80 dB
Why does moving away from a radio affect the loudness you hear?
because sound waves spread out, intensity decreases with distance from the source.
How does distance affect intensity of radiation?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
By how many times must the distance from a point source be increased to reduce the sound intensity by half?
Increase the distance by 70.7% . To 1.707 times the original distance.
Why does the intensity decrease with the square of the distance from a point source?
Intensity is defined as energy per unit area. As we move away from the point source, the area over which the energy distributes is generally spherical or hemispherical. The area of a sphere or hemisphere increases proportional to the square of radius, where the radius in this case is the distance from the point source. Thus Intensity, which is inversely proportional to area, decreases with the square of distance. Hope it was clear. Visit MechMinds.ca for any further help!
Which wave property decreases as you get farther away from the source of a sound?
Intensity
What is the maximum distance at which the riveter is still audible?
The intensity of a sound produced by a point source decreases as the square of the distance from the source. Consider a riveter as a point source of sound and assume that the intensities listed in Table 12.1 are measured at a distance 1 m away from the source. What is the maximum distance at which the riveter is still audible? (Neglect losses due to energy absorption in the air.)
What happens to the illuminance when you move away from the light source?
The intensity decreases.
How does light intensity vary with distance form the source?
Light intensity is inversely proportional to the square of the distance: I = k/d2
What happens to the intensity of ionizing radiation when you move away?
The intensity reduces in proportion to the square of your distance from the source.
What happens to the light intensity if you tripled the distance to the source?
For example, assume you are shining a flashlight at the wall. If you move twice as far from the wall, the spot of light will be twice the diameter. If the diameter doubles, then the area of the spot is 4 times as big. Thus, the same light is lighting 4 times as much wall. Thus, the intensity is 1/4 of the original intensity. The intensity varies with the inverse of the square of the distance.
What is the relationship between the intensity of the radiation given off from a radiation source and distance from the radiation source?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
