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By how many times must the distance from a point source be increased to reduce the sound intensity by half?
Wiki User
∙ 12y ago
Increase the distance by 70.7% .
To 1.707 times the original distance.
Wiki User
∙ 12y ago
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How does light intensity vary with distance form the source?
Light intensity is inversely proportional to the square of the distance: I = k/d2
What happens to the intensity of ionizing radiation when you move away?
The intensity reduces in proportion to the square of your distance from the source.
How is the intensity of a sound related to the distance between the source and the receiver?
The intensity of a sound will decrease according to an inverse square law.
What is the relationship between the intensity of the radiation given off from a radiation source and distance from the radiation source?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
How does distance affect intensity of radiation?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
What distance increase is needed to reduce a sound's intensity from an initial 100dB to a final 80dB?
Sound intensity is inversely proportional to the square of the distancefrom the source.-- Increase the distance from the source by 10 times.-- Sound intensity decreases to 1/102 = 1/100 .-- 10 log ( 1/100 ) = -20 dB-- 100 dB - 20 dB = 80 dB
How does light intensity vary with distance form the source?
Light intensity is inversely proportional to the square of the distance: I = k/d2
What happens to the intensity of ionizing radiation when you move away?
The intensity reduces in proportion to the square of your distance from the source.
What is the relationship between the intensity of the radiation given off from a radiation source and distance from the radiation source?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
How does the intensity of a sound wave change if the distance from the source increases by a factor of 2?
The intensity increases by a factor of 4-APEX
How is the intensity of a sound related to the distance between the source and the receiver?
The intensity of a sound will decrease according to an inverse square law.
How do the amplitude and the intensity of surface water waves vary with the distance of the source?
physics
What is the purpose of the square root?
The purpose of a square root is to enable some calculations, For example,if you have a square with sides of 1 unit, then its diagonal has length sqrt(2) units,the power output of a sound wave is related to the square root of its amplitudethe intensity of light (or magnetic force, gravity) is inversely proportional to the square of the distance from the source so you would have to change the distance by *sqrt(x) to reduce the intensity to 1/x (increase the distance to sqrt(3) times as much to reduce the intensity to 1/3.
How does distance affect intensity of radiation?
The source doesn't care how far you are from it, or whether you're even there, andthere's no relationship between that and the intensity of the radiation it gives off.However, the intensity of the radiation that you receivefrom it is inversely proportionalto the square of your distance from it ... same math as for gravity.
How does the intensity of a sound wave change if the distance from the source is reduced by a factor of 4?
- 6 dB is incorrect. It will decrease by 12 dB.
Why does the intensity of a sound decrease as the distance from the source increases?
the waves spread out over a larger areathe waves are absorbed by the medium as they pass through itthe waves are being scattered by irregularities in the medium and don't all proceed forwardetc.
How does intensity vary with distance from the source?
It's an inverse-square law - for instance, double the distance, and the intensity will be reduced by a factor 1/4.This assumes that there is nothing absorbing the light (for instance, fog); if there is, the intensity in the above example will of course be even less than 1/4 the original intensity.
