If you are inside the train then you can use a device called an accelerometer.
If you are outside the train then you can time how long it takes the train to travel two successive distances, and use the SUVAT equations to determine it speed over each of the distances.
The velocity direction is changing due to the curved track, thus "change in velocity" is acceleration.
If the train is moving at a constant velocity, and therefore in an intertial reference frame, then, no, you could not tell that you were moving.
To convert m/s into km/hr, you multiply by 18/5. So 36 m/s is 129.6 km/hr
This depends on how you define your axes. Let's assume they're defined as normal (being positive is accelerating, negative is breaking, and for velocity positive is driving forward, negative is driving in reverse). Then of course, you are speeding up. This simply means the train was in reverse, but it's accelerating in the positive direction now.
We all grew up thinking "acceleration" means "speeding up". It doesn't."Acceleration" means the speed or the direction is changing.So if a moving object is speeding up, slowing down, or keeping a constant speedon a path that's curving or bending, then there's acceleration going on.
The train will reach 1000 m/s after 34.0 seconds, it will have travelled 17006.8 metres by that time.
0. Doesn't matter what unit it is. If it's moving at a constant velocity, not changing its speed (either positively or negatively), it's not accelerating, right? So its acceleration is 0. However, we must remember to always define; 'with respect to what'. Velocity is a relative concept. i.e. If you are sitting at rest or walking with constant velocity on a train, yet the train is accelerating, are you accelerating? wrt the train - the answer is no. wrt the embankment - the answer is yes. The answer then relates to something else, which is your own 'centre of mass' inertial rest frame. (i.e. you can 'feel' acceleration). So wrt your 'previous' state. This is normally quite poorly understood.
If anything is traveling at constant velocity, then the net force acting on it must be zero.+++Strictly, it is travelling at constant speed, not velocity, because you have not specified the directions of the train and the retarding forces acting on it.
If the train is moving at a constant velocity, and therefore in an intertial reference frame, then, no, you could not tell that you were moving.
if a train is accelerating on a curved track at a constant speed is the train acceeratng
To convert m/s into km/hr, you multiply by 18/5. So 36 m/s is 129.6 km/hr
This depends on how you define your axes. Let's assume they're defined as normal (being positive is accelerating, negative is breaking, and for velocity positive is driving forward, negative is driving in reverse). Then of course, you are speeding up. This simply means the train was in reverse, but it's accelerating in the positive direction now.
Do your own homework! The train travelling at the constant speed will still be doing 16ms after 10 seconds The other train adds 1m per second so, after 10 seconds it will have added 10, 10 + 8 = 18ms. It is going faster. or : you can find the final velocity : final velocity = vi+a(t) = 8+1(10) =18 m/s So Train B is faster.
We all grew up thinking "acceleration" means "speeding up". It doesn't."Acceleration" means the speed or the direction is changing.So if a moving object is speeding up, slowing down, or keeping a constant speedon a path that's curving or bending, then there's acceleration going on.
The train will reach 1000 m/s after 34.0 seconds, it will have travelled 17006.8 metres by that time.
The velocity of the person is the velocity of the speeding train plus the velocity of the jump out. this gives a resultant velocity with a forward component in the direction of the train's motion.
If the train is going at a constant speed, it will make no difference whether she runs forward or backward. There will only be a difference if it is accelerating or slowing down. If it is accelerating you tend to be thrown backward, so it is easier to run back than forward. If it is braking you are thrown forward so it is easier to run forward than backward. The force on the body is the product of the acceleration or retardation and the mass of the body: F (Newtons) = mass (kg) x acceleration (meters/sec2)
No, it is controlled by simply breaking and accelerating. They might derail (go off the track) only if they are going too fast on a turn