0
What else can I help you with?
Why is a train that is traveling on a curved track at a constant speed accelerating?
We all grew up thinking "acceleration" means "speeding up". It doesn't."Acceleration" means the speed or the direction is changing.So if a moving object is speeding up, slowing down, or keeping a constant speedon a path that's curving or bending, then there's acceleration going on.
If a train is slowing down is it accelerating?
This depends on how you define your axes. Let's assume they're defined as normal (being positive is accelerating, negative is breaking, and for velocity positive is driving forward, negative is driving in reverse). Then of course, you are speeding up. This simply means the train was in reverse, but it's accelerating in the positive direction now.
If a train is accelerating at a rate of 4km per hour per second and its initial velocity is 20km per hour what is its velocity after 30 seconds?
The train's velocity after 30 seconds can be calculated using the formula: final velocity = initial velocity + (acceleration * time). Plugging in the values, final velocity = 20 km/hr + (4 km/hr/s * 30 s) = 20 km/hr + 120 km/hr = 140 km/hr. So, the train's velocity after 30 seconds is 140 km/hr.
What is steady velocity?
Steady velocity refers to a constant and unchanging speed and direction of an object's motion over time. It means that the object is moving at a consistent rate without any acceleration or deceleration.
If a train leaves a station at 0.0 marker traveling with a constant velocity of 36.0msWhat is the velocity a of the train in kmh?
To convert m/s into km/hr, you multiply by 18/5. So 36 m/s is 129.6 km/hr
What is the acceleration of any object moving at constant velocity?
0. Doesn't matter what unit it is. If it's moving at a constant velocity, not changing its speed (either positively or negatively), it's not accelerating, right? So its acceleration is 0. However, we must remember to always define; 'with respect to what'. Velocity is a relative concept. i.e. If you are sitting at rest or walking with constant velocity on a train, yet the train is accelerating, are you accelerating? wrt the train - the answer is no. wrt the embankment - the answer is yes. The answer then relates to something else, which is your own 'centre of mass' inertial rest frame. (i.e. you can 'feel' acceleration). So wrt your 'previous' state. This is normally quite poorly understood.
What is the net force on the different cars of a subway train that is traveling at constant velocity?
If anything is traveling at constant velocity, then the net force acting on it must be zero.+++Strictly, it is travelling at constant speed, not velocity, because you have not specified the directions of the train and the retarding forces acting on it.
Why is a train that is traveling on a curved track at a constant speed accelerating?
We all grew up thinking "acceleration" means "speeding up". It doesn't."Acceleration" means the speed or the direction is changing.So if a moving object is speeding up, slowing down, or keeping a constant speedon a path that's curving or bending, then there's acceleration going on.
If a train is slowing down is it accelerating?
This depends on how you define your axes. Let's assume they're defined as normal (being positive is accelerating, negative is breaking, and for velocity positive is driving forward, negative is driving in reverse). Then of course, you are speeding up. This simply means the train was in reverse, but it's accelerating in the positive direction now.
If a train is accelerating at a rate of 4km per hour per second and its initial velocity is 20km per hour what is its velocity after 30 seconds?
The train's velocity after 30 seconds can be calculated using the formula: final velocity = initial velocity + (acceleration * time). Plugging in the values, final velocity = 20 km/hr + (4 km/hr/s * 30 s) = 20 km/hr + 120 km/hr = 140 km/hr. So, the train's velocity after 30 seconds is 140 km/hr.
Two trains leave a station at the same time train A travels at a constant of 16ms train B starts at 8.0 ms but accelerates constantly at 1o ms After 10.0 seconds which train has the greater speed?
Do your own homework! The train travelling at the constant speed will still be doing 16ms after 10 seconds The other train adds 1m per second so, after 10 seconds it will have added 10, 10 + 8 = 18ms. It is going faster. or : you can find the final velocity : final velocity = vi+a(t) = 8+1(10) =18 m/s So Train B is faster.
Demonstrate in terms of force what the net force would be on the girl running on a train if she runs towards the front of the train and if she runs towards the back of the train?
If the train is going at a constant speed, it will make no difference whether she runs forward or backward. There will only be a difference if it is accelerating or slowing down. If it is accelerating you tend to be thrown backward, so it is easier to run back than forward. If it is braking you are thrown forward so it is easier to run forward than backward. The force on the body is the product of the acceleration or retardation and the mass of the body: F (Newtons) = mass (kg) x acceleration (meters/sec2)
Is there some way you can steer a train?
No, it is controlled by simply breaking and accelerating. They might derail (go off the track) only if they are going too fast on a turn
What is steady velocity?
Steady velocity refers to a constant and unchanging speed and direction of an object's motion over time. It means that the object is moving at a consistent rate without any acceleration or deceleration.
If a train leaves a station at 0.0 marker traveling with a constant velocity of 36.0msWhat is the velocity a of the train in kmh?
To convert m/s into km/hr, you multiply by 18/5. So 36 m/s is 129.6 km/hr
Would you know you're moving in a train if there was no friction and you could not see out of the train ie can't see objects going past?
No, without any external reference points to visually determine movement, you would not be able to perceive that you are moving on a train if there is no friction. The lack of friction would eliminate the physical sensations typically associated with movement.
How does friction affect the velocity of a train?
Friction between the train wheels and the tracks can slow down the velocity of a train by converting its kinetic energy into heat. Higher friction can cause more resistance, which can decrease the train's velocity. Conversely, lower friction or well-lubricated tracks can reduce the impact of friction on the train's velocity.
