Wow, you are SUCH an inspiration! I love my crckopot too. I actually have 3 of them, a mini one for dips, a medium size, and a large one. Unfortunately, I broke the glass lid to my large crckopot yesterday. Shattered everywhere! I have to adjust my menu planning until I can get a replacement lid. Thanks so much for sharing and cheering us on too!
If the wire's cross-section area is constant, then its resistance per unit length is constant, and the total resistance should be directly proportional to the length of a wire segment.
The resistance of the wire is directly proportional to the length and inversely proportional to the area of cross section. Also it depends on the material of the wire with which it is made. So three factors. Length, area of cross section, material.
When it is on the cross-sectional area it is inversely proportional to the wire,otherwise it is directly proportional to the wire.
Yes, resistance is directly proportional to the length, and inversely proportional to the cross sectional area. R = p*l/A. Where R is the resistance of the piece of conducting material, p is Greek letter rho, representing the resistivity of the material, l (lower case L) is the length, and A is the area.
Because resistance is inversely proportional to the cross sectional area of the wire and directly proportional to its length. R = p*L/A, where R is resistance (in Ohms), p is resistivity (property of the material, in Ohms*m), L and A are length and area of the wire. And if you think about it, it makes perfect sense. In thick wire electrons have a lot of 'room' to move, they do not obstruct the path. If you imagine it is like a road with many free lanes - cars move fast and freely i.e. low resistance (or more scientifically, like many wires in parallel). Where as length is proportional to the resistance, since every small segment of wire adds more resistance to the total (many wires in series).
If the wire's cross-section area is constant, then its resistance per unit length is constant, and the total resistance should be directly proportional to the length of a wire segment.
resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.
If you have a conductor ... say, a copper wire ... and you keep its diameter and temperatureconstant, then yes, its resistance will be directly proportional to its length.
The resistance of the wire is directly proportional to the length and inversely proportional to the area of cross section. Also it depends on the material of the wire with which it is made. So three factors. Length, area of cross section, material.
Yes, the resistance is directly proportional to length of wire and inversely proportional Area, hence when Length of wire increases the resistance also increases and when Area increases the resistance decreases. This means a thick wire has least amount of Electrical resistance.
When it is on the cross-sectional area it is inversely proportional to the wire,otherwise it is directly proportional to the wire.
Assuming the wire follows Ohm's Law, the resistance of a wire is directly proportional to its length therefore doubling the length will double the resistance of the wire. However when the length of the wire is doubled, its cross-sectional area is halved. ( I'm assuming the volume of the wire remains constant and of course that the wire is a cylinder.) As resistance is inversely proportional to the cross-sectional area, halving the area leads to doubling the resistance. The combined effect of doubling the length and halving the cross-sectional area is that the original resistance of the wire has been quadrupled.
The wire resistance is proportional to the length of wire divided by its cross-section area. The voltage drop is proportional to the resistance times the current.
Yes, resistance is directly proportional to the length, and inversely proportional to the cross sectional area. R = p*l/A. Where R is the resistance of the piece of conducting material, p is Greek letter rho, representing the resistivity of the material, l (lower case L) is the length, and A is the area.
Resistance is directly proportional to the resistivity and length of the conductor, and inversely-proportional to its cross-sectional area. As resistivity is affected by temperature, we can say that temperature indirectly affects resistance.
The resistance is directly proportional to the length of conductor and inversely proportional to area of the cross section.If the length is doubled then the resistance will double.Resistance=rho*l/arho=resistivity of the material (Ohms/m) and depends on the material used for the wirel=length of the wirea= area of the cross section of the wire.
The thermal resistance of a wire is proportional to ln(r2/r1), meaning that a thicker wire has a greater thermal resistance.