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Sucrose has a anomeric carbon which is not free since the carbon links glucose and fructose and fructose doesn't have free OH group to under reducing reaction and to open the ring so sucrose is non reducing. In the formation of sucrose ,1,2glycosidic bond is formed between glucose and fructose. In the process, the keto group on Carbon-2 of the fructose molecule and the aldehyde group on Carbon 1 of the glucose molecule are altered. Know that keto group and aldehyde group give a monosaccharides and disaccharides the reducing properties.

Sucrose is a non-reducing sugar because it does not have free ketone or aldehyde group in its ring form

because sucrose has no hemiacetal linkage

sucrose is a disaccharide as it contains glucose and fructose linked by a glycosidic linkage. it is non-reducing because it does not contain any free aldehyde or keto group.

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Related Questions

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A substance could taste sweet due to the presence of natural sugars, while giving a negative reaction with Benedict's solution if the sugar present is a non-reducing sugar. Non-reducing sugars like sucrose do not react with Benedict's solution because they do not have the free aldehyde or ketone groups required for the reaction.


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Sucrose will not react with Benedict's solution. This is because sucrose is a non-reducing sugar, meaning it does not have a free aldehyde or ketone group that can be oxidized by Benedict's reagent.


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Sucrose would not give a positive test with Fehling's reagent after hydrolysis because sucrose is a non-reducing sugar. During hydrolysis, sucrose is broken down into its monosaccharide components (glucose and fructose), which are reducing sugars and can react with Fehling's reagent to give a positive test for reducing sugars.


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