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Sn4+ is fully oxidised, Sn2+ only half
Stearic hindrance and stability of carbonium ion, less stearic hindrance and less stability of carbonium ion favors the SN2 reaction.
This symbol is Sn2+.
10 isotopes 10 isotopes
A halide ion (I-, Br-, or Cl-) is the most common leaving group of Sn2 reactions
Yes an alkyl halide can undergo both Sn1 and Sn2 reactions - it just depends on what kind of alkyl halide it is. Methyl halides such as CH3Br/CH3Cl/CH3I, etc. are most suitable for Sn2 reactions because they are less sterically hindered by R-groups (they are not "bulky"). This allows for easy attack by the nucleophile. Primary alkyl halides (RCH2X) are also most suitable for Sn2 because of the same reason above Secondary alkyl halides can undergo both Sn1 and Sn2 reactions, this depends on other factors such as solvent and leaving group and nucleophile. If the solvent is polar aprotic, the reaction will go Sn2, if polar protic - Sn1. Tertiary alkyl halides (alkyl halides with 4 r-groups) do not go Sn2 because they are bulky and the R-groups stabilize the carbocation by hyperconjugation and inductive effect.
An SN2 reaction is a one step bimolecular substitution mechanism which is 2nd order in kinetics. An electron rich species (called a nucleophile) attacks an electrophile (electron deficient species) while a leaving group (LG) leaves. Typically a good nucleophile for an SN2 reaction are halides and moderate to strong bases. Good leaving groups are species that are stable on their own like halides, water, tosylate, and protonated ethers. Conditions for an SN2 reaction are similar to the conditions necessary for an E2 elimination reaction; the two are in constant competition.
because the bond between the halogen and the carbon in the benzene ring (aryl halide) or a carbon participating in a double bond (vinylic halide) is much too strong--stronger than that of an alkyl halide--to be broken by a nucleophile (Sn2). Also the electrons of the double bond or benzene ring repel the approach of a nucleophile from the backside. They do not undergo Sn1 reactions because the carbocation intermediate they would produce is unstable and does not readily form.
Quite the opposite: halides are far LESS reactive than halogens.A halide is a binary compound consisting of one halogen atom plus one atom, or radical, of "something else" that's electropositive to the halogen. (Which isn't hard to be.)Fluorine is a halogen, and it's very reactive. If you mix some sodium with it, it becomes a non-reactive halide; they put tons of this stuff in toothpaste and so far no one's reported having it cause their teeth to explode.Chlorine is also a reactive halogen, but mix it with sodium and it becomes table salt.
A reaction with alkyl halides in NaI with acetone is by the Sn2 mechanism. The rate for an Sn2 mechanism is directly proportional to the concentration of the nucleophile: rate = k[nucleophile][alkylhalide] If the iodine solution (the nucleophile) is half as concentrated, then the rate will also be halved. rate = k [nucleophile]/2 [alkyl halide]
Sn4+ is fully oxidised, Sn2+ only half
sn2
Oxidation!
Stearic hindrance and stability of carbonium ion, less stearic hindrance and less stability of carbonium ion favors the SN2 reaction.
This symbol is Sn2+.
This cation is Sn2+.
This follows a Sn2 reaction.