In chemical bonding, only the valence shell electrons participate in reactions in general conditions. Sulfur has 6 electrons in its third energy level, outermost shell. Therefore the highest oxidation number for sulfur is +6.
No, oxygen will never have a -3 oxidation number. If it had a -3 oxidation number, it would not have a full octet. It would have a +1 charge, therefore making it not happy.
Noble gases, also known as group 18 elements, will never have an oxidation number because they have a full valence shell of electrons, making them very stable and unreactive.
The oxidation number of F, or Fluorine, is F-1. Since it is in the seventh group on the periodic table, it has seven valence electrons. It needs to get eight valence electrons to be stable, so it will gain one electron.
It never has -2 oxidation number. Nitrogen oxidation numbers are possible: -3 (nitrides), 0 (elemental), +3 (nitrites), +5 (nitrates). Also +1, +2 and maybe +4 are possible (in Nitro-oxides only).
Never heard of an Oxidation plug?
Numbers have no end. There is an infinite number of numbers. They never stop going higher and higher.
A number is never divisible by one higher than it.
No, that is not possible for Chlorine. Some elements have more than one oxidation number, such as Iron, Mercury, Copper, etc, but Chlorine only wants to gain one electron. If it had a -2 charge, it would not be stable, so that would never happen.
Noble gases, such as helium, neon, argon, krypton, xenon, and radon, will never have a positive oxidation number. This is because they have a full outer electron shell, making them stable and unreactive.
lead (IV) ion is Pb4+ ion. Note that Pb4+ is never found as an ion- the (IV) is an oxidation number or oxidation state.
Zn is a d block element. Oxidation number of it is +2.
HCN ( hydrogen cyanide) has the structurte H-C///N ( /// = triple bond). The oxidation number of an atom is the number of outer most electrons used in forming a bond. Not all the outer most electrons are used, some can remain as 'lone pairs'. Carbon ALWAYS has an oxidation no. of '+4' . It never varies. Hydrogen has an oxidaton number of '+1'. It is the nitrogen that has the variable oxidation. number. HCN forms the ions , H^(+) & CN^(-) Since carbon is always '4' and the overall charge of the ion is '-1' , then we can form a sum . 4 + N = -1 N = -1 -4 N = -5 is the oxid'n no/ of nitrogen in HCN. ( All five of nitrgens outer most electrons are involved in the bonding process. ). Compare with ammonia NH3 , Here nitrogen's oxid'n No. is '3' leaving a 'lone pair' of electrons not used in the outer most electron shell.