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Why is the period of the pendulum dependent on the length of string?
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What is the period of a 25 kg pendulum with a length of 45 m?
A simple pendulum with a length of 45m has a period of 13.46 seconds. If the string is weightless, then the mass of the bob has no effect on the period, i.e. it doesn't matter.
How does the pendulum get affected by the length of string?
The shorter the string - the faster the oscillation.
How does the length of the string affect the period of the pendulum?
Well compare a pendulum with swing. If the swing length is short, you will quickly return back to your middle position. Similarly in a pendulum if you have a long string, the time take to complete one swing will be more. This means Time period is directly proportional to the increase in length . But by various experiments, they have found that T Is proportional to sq root of length. T = 2pi sq root of (length /g) If you wish to clarify physics doubts, please subscribe to my handle @Raj-bi7xp
What is the period of a pedelum?
The period of oscillation of a simple pendulum displaced by a small angle is: T = (2*PI) * SquareRoot(L/g) where T is the period in seconds, L is the length of the string, and g is the gravitional field strength = 9.81 N/Kg. This equation is for a simple pendulum only. A simple pendulum is an idealised pendulum consisting of a point mass at the end of an inextensible, massless, frictionless string. You can use the simple pendulum model for any pendulum whose bob mass is much geater than the length of the string. For a physical (or real) pendulum: T = (2*PI) * SquareRoot( I/(mgr) ) where I is the moment of inertia, m is the mass of the centre of mass, g is the gravitational field strength and r is distance to the pivot from the centre of mass. This equation is for a pendulum whose mass is distributed not just at the bob, but throughout the pendulum. For example, a swinging plank of wood. If the pendulum resembles a point mass on the end of a string, then use the first equation.
Time period of a pendulum?
For a heavy weight on the end of a weightless string ("a simple pendulum") the period is 2.pi.squareroot(L/g) where L is the length of the string and g is the acceleration due to gravity. If the weight of the pendulum is not wholly at the end (as in a heavy rod instead of a light string) then replace L by k2/L where L is (as before) the distance to the centre of gravity below the suspension point, and k is the radius of gyration of the whole suspended part, inculding the arm of the pendulum as well as any weights ("compound pendulum").
In simple pendulum if string is flexible then what is effect on time period?
multiply the length of the pendulum by 4, the period doubles. the period is proportional to the square of the pendulum length.
How is frequency of a pendulum related to the length of the pendulum string?
The period of the pendulum is (somewhat) inversely proportional to the square root of the length. Therefore, the frequency, the inverse of the period, is (somewhat) proportional to the square root of the length.
What is the period of a 25 kg pendulum with a length of 45 m?
A simple pendulum with a length of 45m has a period of 13.46 seconds. If the string is weightless, then the mass of the bob has no effect on the period, i.e. it doesn't matter.
Explain how the length of a string affects the motion of a simple pendulum?
You mean the length? We can derive an expression for the period of oscillation as T = 2pi ./(l/g) Here l is the length of the pendulum. So as length is increased by 4 times then the period would increase by 2 times.
How does the pendulum get affected by the length of string?
The shorter the string - the faster the oscillation.
How does a pendulums period vary with the length of its mass With Gravitational acceleration?
The length of the pendulum is measured from the pendulum's point of suspension to the center of mass of its bob. Its amplitude is the string's angular displacement from its vertical or its equilibrium position.
What is the relationship between the length of the string of a pendulum and the number of swings?
There's no relationship between the length of the pendulum and the number of swings.However, a shorter pendulum has a shorter period, i.e. the swings come more often.So a short pendulum has more swings than a long pendulum has in the same amountof time.
How does the length of the string affect the period of the pendulum?
Well compare a pendulum with swing. If the swing length is short, you will quickly return back to your middle position. Similarly in a pendulum if you have a long string, the time take to complete one swing will be more. This means Time period is directly proportional to the increase in length . But by various experiments, they have found that T Is proportional to sq root of length. T = 2pi sq root of (length /g) If you wish to clarify physics doubts, please subscribe to my handle @Raj-bi7xp
What affects a pendulum?
The mass of the pendulum, the length of string, and the initial displacement from the rest position.
Which of these pendulums would have the greatest length measured in meters a pendulum with a period of 2 seconds or a pendulum with a period of 1.5 seconds?
It doesn't matter what unit you use to measure the physical length of the pendulum. As a matter of fact, it doesn't matter what unit you use to measure the duration of its period either. If both are at rest on the same planet, then the penduum with the longer string has the longer period. Period!
What controls the period of a pendulum?
For a simple pendulum, consisting of a heavy mass suspended by a string with virtually no mass, and a small angle of oscillation, only the length of the pendulum and the force of gravity affect its period. t = 2*pi*sqrt(l/g) where t = time, l = length and g = acceleration due to gravity.
What is the period of a pedelum?
The period of oscillation of a simple pendulum displaced by a small angle is: T = (2*PI) * SquareRoot(L/g) where T is the period in seconds, L is the length of the string, and g is the gravitional field strength = 9.81 N/Kg. This equation is for a simple pendulum only. A simple pendulum is an idealised pendulum consisting of a point mass at the end of an inextensible, massless, frictionless string. You can use the simple pendulum model for any pendulum whose bob mass is much geater than the length of the string. For a physical (or real) pendulum: T = (2*PI) * SquareRoot( I/(mgr) ) where I is the moment of inertia, m is the mass of the centre of mass, g is the gravitational field strength and r is distance to the pivot from the centre of mass. This equation is for a pendulum whose mass is distributed not just at the bob, but throughout the pendulum. For example, a swinging plank of wood. If the pendulum resembles a point mass on the end of a string, then use the first equation.
