Because of high of heat of Hydration of HF ( Fluoride ion is extensively hydrated because of it's small size )
HF has greater enthalpy of neutralization due to very high enthalpy of hydration of fluoride ion
SINCE CARBONATE & HYDROXIDE'S ARE NEGATIVE ELEMENTS(eg..OH-) WHEN USED WITH ACIDIC (pH<7)ENVIRONMENT (i.e..POSITIVE ELEMENTS( H+))FORMS A NEUTRAL COMPOUND.HENCE USED FOR NEUTRALIZATION.
Technically it is called water because the positive hydrogen ions and the negative hydroxide ions would attract to form a compound with two hydrogen molecules and one oxygen molecule. H2O. This occurs most often in acid-base neutralization reaction where water is a product of the reactions.
I think it is a positive charge!!
They have a negative charge and the formula OH.
Nitrate (NO3^-), because the Hydroxide ion also has a negative one charge (OH^-)
A negative enthalpy of formation indicates that energy is evolved.
SINCE CARBONATE & HYDROXIDE'S ARE NEGATIVE ELEMENTS(eg..OH-) WHEN USED WITH ACIDIC (pH<7)ENVIRONMENT (i.e..POSITIVE ELEMENTS( H+))FORMS A NEUTRAL COMPOUND.HENCE USED FOR NEUTRALIZATION.
Exothermic, because the reaction enthalpy must be negative. With polymerization, the entropy decreases. The Gibbs energy has to be negative. Thus negative reaction enthalpy. Gibbs energy = reaction enthalpy - temperature*entropy
Two things produced by neutralization are water and a salt. Water is formed as a result of the reaction between the hydrogen ions from an acid and the hydroxide ions from a base. A salt, which is an ionic compound, is formed when the positive ions from the base combine with the negative ions from the acid.
Negtive
The hydroxide ion, OH-, has a negative charge of 1-.
Yes, hydroxide (OH-) ions have a negative electrical charge.
Actually your question should sound "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?". This is because when STRONG ACID and STRONG BASE react and neutralization process occur, a complete ionization will occur. Therefore, they will have almost the same value of enthalpies and can be assummed to be -57.2kJmol-1. As per mentioned that if your question sounds "Why is the enthalpy change of neutralization of STRONG ACID and STRONG BASE equal to -57.2kJmol-1?", then my explaination above will be helpful. However, if it doesn't sound like mine and you insisted with your question titled "Why is the enthalpy change of neutralization equal to -57.2kJmol-1", then my answer is that they didn't equal to -57.2kJmol-1 and it varies from the list of reactants. 1. STRONG acid + STRONG base = -57.2 2. WEAK acid + WEAK base = less than 57.3kJmol-1 3. WEAK acid + STRONG base = more negative than -57.3kJmol-1 Wish that it is useful as your reference. Prompt me if I am wrong.
Enthalpy- positive Entropy- decreasing Free energy- negative
electron affinity is the negative of electron gain enthalpy. for example, the electron gain enthalpy of fluorine is -328, and electron affinity is 328 which is -(-328)
hydroxide
The equation for ∆G is ∆G = ∆H - T∆S H is enthalpy and S is entropySo, ∆G is negative if T∆S is greater than ∆H