The gravitational attraction is not by anything special in the center of the Earth; instead, it is the sum of the attraction by every individual atom.
For an object in the center of the Earth, the pull in one direction will be exactly compensated by the pull in another direction.
So it turns out that if you're anywhere inside a solid sphere, it acts as if none of the mass OUTSIDE of your
position is there. You're only affected by the mass of the smaller sphere INSIDE your position, as if you were
on its surface, and the 'shell' outside of your position had gone away.
The weight is zero at the center of the earth. since F= G M.m / 2 d at the center of the earth the distance is zero from the center thus no force is imaginable. a more profound explanation is that at the center you are being puled by every particle from all sides with equal forces, the net force is logically zero.
since weight=mg
and gravity at center of earth is zero(g=0)
so weight is zero
zero
Here's a nice general rule to ponder: At the center of mass of any planet ... whichis the center of the planet if its mass is distributed uniformly and symmetrically ...the weight of any object due to gravitational attraction is zero.
At the earth's center, the acceleration/force of gravity is theoretically zero.(At least the force of gravity between the earth and an object at its center. There's still the gravitational forcesbetween the object and everything else ... the sun, moon, stars, etc.)
The mass of an object is the same wherever the object is (even outer space), but its weight depends on how the mass is affected by gravity. So it's convenient to measure weight using scales. If the object was sitting on some scales as they were both falling to earth the scales would show zero because there would be no pressure from the object.
potential depends on the charge of the object , as any object connected to earth can have no charge on it so the potential of any object connected to earth becomes zero.
zero
weight of an object is minimum when it is placed at the center of the earth because when an object is in the center ,it experiences gravitational pull from all the sides.thus the net weight of an object remains to be zero. +++ Possibly, but given that the centre of the Earth is unreachable and a ball of metal anyway, a more useful and achievable location for weightlessness is in Space!
Zero
The weight of an object is its mass times the acceleration of gravity. The acceleration of gravity at the center of the Earth is zero. A 1 kg mass at the center of the Earth still has a mass of 1 kg, but the force of attraction between the 1kg mass and all the other mass around it will add up to zero.
AS WE KNOW, that there is the force of gravity at the center of Earth, if every part or portion of earth has its weight then net weight of the earth will be zero........
Here's a nice general rule to ponder: At the center of mass of any planet ... whichis the center of the planet if its mass is distributed uniformly and symmetrically ...the weight of any object due to gravitational attraction is zero.
In the cavity at the center of the Earth, your weight would be zero, because you would be pulled equally by gravity in all directions. - The gravitational field of Earth at its center is zero.
Yes, at the center it becomes zero.
The weight of a person is not constant at all places on the Earth. The weight becomes zero at the center of the earth or far away from the Earth.
In the middle of the earth is where an object has the lightest weight. The weight is zero. The reason is that the mass of the object is pulled equally in all directions so all the forces cancel out.
At the earth's center, the acceleration/force of gravity is theoretically zero.(At least the force of gravity between the earth and an object at its center. There's still the gravitational forcesbetween the object and everything else ... the sun, moon, stars, etc.)
w=mg gravity is zero at centre of earth then g=0 and w=m(0) =0 so weight is zero