0
What else can I help you with?
What will happen to the value of g if the compound pendulum is taken nearer to the centre of earth?
The value of g would increase if the compound pendulum is taken nearer to the center of the Earth. This is because gravity is stronger closer to the Earth's surface. Conversely, if the compound pendulum is moved further away from the center of the Earth, the value of g would decrease.
What is the value of g at the centre of earth in detail?
The value of acceleration due to gravity (g) at the center of Earth is theoretically zero. This is because the mass surrounding the center exerts equal gravitational force in all directions, effectively canceling each other out at the center point.
IS VALUE OF g at centre of the earth maximum?
No, at the center of the Earth, it would be zero. That's because the gravitation of different parts of the Earth, in different directions, would cancel.
Why value of 'g' decreases due to increase in length?
as we go far from earths surface the value of g decreases this is because g is inversely proportional to the value of r^2(which is the distance of the body from the center of the earth.
Is the value 'g' same everywhere on the surface of the earth?
No, there are slight variations, due to (a) the fact that some points are closer to Earth's center (a.1, you may be on a mountain, and a.2, the poles are closer to the Earth's center), (b) the centrifugal pseudoforce, which gets stronger as you approach the equator, and (c) any gravitational anomaly caused by an uneven distribution of masses.
What is the value of G at center of earth?
Zero.
If an object is moving away from earth what will be value of g?
The value of the acceleration due to gravity (g) depends on the mass of the Earth and the distance from its center. As an object moves away from Earth, the value of g will decrease because the gravitational force weakens with distance.
What will happen to the value of g if the compound pendulum is taken nearer to the centre of earth?
The value of g would increase if the compound pendulum is taken nearer to the center of the Earth. This is because gravity is stronger closer to the Earth's surface. Conversely, if the compound pendulum is moved further away from the center of the Earth, the value of g would decrease.
What is the value of g at the centre of earth in detail?
The value of acceleration due to gravity (g) at the center of Earth is theoretically zero. This is because the mass surrounding the center exerts equal gravitational force in all directions, effectively canceling each other out at the center point.
Why value of 'g' decreases when you go inside the earth?
Because the value of "g" varies directly with the sum of the masses of the two bodies acted upon by the force of gravity. If you go inside the earth, only part of the mass of the earth will be attracting you toward its center; the mass of the part of the earth that is farther from the center than you are will be attracting you away from the center. If it were possible to reach the center of the earth, the value of "g" would reach zero because the mass of the earth would be acting upon equally you in all directions.
IS VALUE OF g at centre of the earth maximum?
No, at the center of the Earth, it would be zero. That's because the gravitation of different parts of the Earth, in different directions, would cancel.
Why value of 'g' decreases due to increase in length?
as we go far from earths surface the value of g decreases this is because g is inversely proportional to the value of r^2(which is the distance of the body from the center of the earth.
Is the value 'g' same everywhere on the surface of the earth?
No, there are slight variations, due to (a) the fact that some points are closer to Earth's center (a.1, you may be on a mountain, and a.2, the poles are closer to the Earth's center), (b) the centrifugal pseudoforce, which gets stronger as you approach the equator, and (c) any gravitational anomaly caused by an uneven distribution of masses.
What is the value of g at depth of earth?
The gravitational force decreases when you go deeper within the Earth. That is because part of the Earth will be above you, and therefore pull you up. your wrong my friend: in Thermodynamics by Cenjel: It is interesting to note that at locations below sea level, the value of g increases with distance from the sea level, reaches a maximum at about 4500 m, and then starts decreasing. (What do you think the value of g is at the center of the earth?)
What is the value of g at a distance from the Earth's center equal to 4 times the Earth's radius if the value of g at the earth's surface is about 9.8 meters per second squared?
The gravitation field varies inversely with the square of distance, in this case as measured from the Earth's center. We live on the surface, which is at a distance of 1R where R is the radius. At a distance 4 times greater (4R), the force would fall to 1/4^2 = 1/16 time g. (9.8)/16 = etc.
How much above the surface of earth does the acceleration due to gravity reduces by 36 percent of its value on the surface of earth radius of earth equals 6400 km?
The acceleration due to gravity decreases with distance from the center of the Earth. Using the formula for gravitational acceleration (g) at a distance (r) from the center of the Earth: ( g' = \frac{G \cdot M}{(r+a)^2} ), where a is the radius of the Earth and G is the gravitational constant, you can calculate the distance above the surface of the Earth at which the acceleration due to gravity reduces by 36 percent.
What will happen to value of g if compound pendulum is taken nearer to the centre of the earth?
The acceleration of gravity decreases as the observation point is taken deeper beneath the surface of the Earth, but it's not the location of the compound pendulum that's responsible for the decrease.
