The gravitational force decreases when you go deeper within the Earth. That is because part of the Earth will be above you, and therefore pull you up.
your wrong my friend:
in Thermodynamics by Cenjel:
It is interesting to
note that at locations below sea level, the value of g increases with distance
from the sea level, reaches a maximum at about 4500 m, and then starts
decreasing. (What do you think the value of g is at the center of the earth?)
g= acceleration due to gravity.
The acceleration due to gravity is 0 at the centre of the Earth.
The mass of the Earth is pulling equally in all directions, thereby cancelling itself out.also in the center of earth there is no mass to attract the body towards itself so value of g is 0
0 because its at the center of earth,meaning it cant pulled anywhere. This also means that once an object is at the center of earth, it cannot escape due ti the gravity's strength.
i think value of g becomes zero
Zero.
The acceleration of gravity (value of 'g') is maximum on the earth's surface, and it decreases from there in both directions ... up into the air or down into the earth.
as we go far from earths surface the value of g decreases this is because g is inversely proportional to the value of r^2(which is the distance of the body from the center of the earth.
at about 9km above the surface of the sea.
G i.e force per unit mass on the earth surface......YES.because all calculation is approximately 10
g will increase when rotation is stopped because:- g depend on following thing;:- first on shape of earth second on rotation....(only Equator) not pole third one on going altitude and depth,...........
value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d
As soon as you go below the surface, it will decrease (dont ask for the calculations) until at its centre where acceleration due to gravity will be 0.
i think value of g becomes zero
Zero.
Zero.
The weight is due to the force exerted on the body by the gravitational pull by the earth. If no such gravitational pull on the body, then the body becomes weightless. In free space, very far away from the earth the astronauts experience weightlessness. So if M is the mass of the body, then Mg is the weight of the body. Hence weight depends on the value of 'g'. The value of g is the least at the equatorial region. It will be maximum at the poles. As we go at higher altitudes g value decreases. Same way as we go towards the centre of the earth ie as depth increases, g value decreases.
The acceleration of gravity (value of 'g') is maximum on the earth's surface, and it decreases from there in both directions ... up into the air or down into the earth.
I think that g (the gravitational constant) varies dependent on your proximity to other massive bodies. For example the value of g on the moon is less than the value of g on earth. It is not constant throughout the universe.
maybe it is bigger in size than the earth.
It's the same as that of Earth but the value of g varies from one object to the other. The value of the gravitational constant or the BIG "G" remains constant. I think you confused it with the LITTLE "g" which is the gravitation of a object (one with mass) or the acceleration due to gravity. The value of g on Earth and Moon is 9.8m/s^2 and 1.6249m/s^2, respectively. I hope this answers you all.