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The gravitational force decreases when you go deeper within the Earth. That is because part of the Earth will be above you, and therefore pull you up.

your wrong my friend:

in Thermodynamics by Cenjel:

It is interesting to

note that at locations below sea level, the value of g increases with distance

from the sea level, reaches a maximum at about 4500 m, and then starts

decreasing. (What do you think the value of g is at the center of the earth?)

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13y ago
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10y ago

g= acceleration due to gravity.

The acceleration due to gravity is 0 at the centre of the Earth.

The mass of the Earth is pulling equally in all directions, thereby cancelling itself out.also in the center of earth there is no mass to attract the body towards itself so value of g is 0

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11y ago

0 because its at the center of earth,meaning it cant pulled anywhere. This also means that once an object is at the center of earth, it cannot escape due ti the gravity's strength.

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Q: What is the value of g at depth of earth?
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Does the value of 'g' remain same everywhere on earth?

G i.e force per unit mass on the earth surface......YES.because all calculation is approximately 10


When earth stops rotating what is the value of g?

g will increase when rotation is stopped because:- g depend on following thing;:- first on shape of earth second on rotation....(only Equator) not pole third one on going altitude and depth,...........


Where the gravitational field strength is maximum?

value of acceleration due to gravity is maximum at the surface of earth. So the gravitational field strength. as g'=g(1-d/R) at surface d=R so d=R so g'=g at earth's centre g=0. Its value decrease with decrease or increase in height. as: g'=g(1-2h/R) ......for height h and g'=g(1-d/R) .....for depth d


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As soon as you go below the surface, it will decrease (dont ask for the calculations) until at its centre where acceleration due to gravity will be 0.


What is the value of 'g' if the earth stops rotating?

i think value of g becomes zero


What is the value of G at center of earth?

Zero.


What is the value of 'g' at center of earth?

Zero.


The weight of an object due to?

The weight is due to the force exerted on the body by the gravitational pull by the earth. If no such gravitational pull on the body, then the body becomes weightless. In free space, very far away from the earth the astronauts experience weightlessness. So if M is the mass of the body, then Mg is the weight of the body. Hence weight depends on the value of 'g'. The value of g is the least at the equatorial region. It will be maximum at the poles. As we go at higher altitudes g value decreases. Same way as we go towards the centre of the earth ie as depth increases, g value decreases.


What will happen to the value of g if the compound pendulum is taken nearer to the centre of earth?

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Value of g in universe?

I think that g (the gravitational constant) varies dependent on your proximity to other massive bodies. For example the value of g on the moon is less than the value of g on earth. It is not constant throughout the universe.


Why is the value of g more at Jupiter than at earth?

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Value of gravitational constant on earth and moon?

It's the same as that of Earth but the value of g varies from one object to the other. The value of the gravitational constant or the BIG "G" remains constant. I think you confused it with the LITTLE "g" which is the gravitation of a object (one with mass) or the acceleration due to gravity. The value of g on Earth and Moon is 9.8m/s^2 and 1.6249m/s^2, respectively. I hope this answers you all.