The gravitational force decreases when you go deeper within the Earth. That is because part of the Earth will be above you, and therefore pull you up.
your wrong my friend:
in Thermodynamics by Cenjel:
It is interesting to
note that at locations below sea level, the value of g increases with distance
from the sea level, reaches a maximum at about 4500 m, and then starts
decreasing. (What do you think the value of g is at the center of the earth?)
If the Earth were to stop rotating, the value of 'g' (acceleration due to gravity) would remain approximately the same at the Earth's surface. The rotation of the Earth does not significantly affect the gravitational pull experienced on the surface.
9.8 is the value for g, which stands for Gravity.
The value of g would increase if the compound pendulum is taken nearer to the center of the Earth. This is because gravity is stronger closer to the Earth's surface. Conversely, if the compound pendulum is moved further away from the center of the Earth, the value of g would decrease.
The value of acceleration due to gravity 'g' at the center of the Earth is theoretically zero because the mass of the Earth surrounds an object equally in all directions, resulting in a net gravitational force of zero at the center.
The average value of acceleration due to gravity (g) on Earth is approximately 9.81 m/s^2. This value can vary slightly depending on location and altitude on Earth.
G i.e force per unit mass on the earth surface......YES.because all calculation is approximately 10
g will increase when rotation is stopped because:- g depend on following thing;:- first on shape of earth second on rotation....(only Equator) not pole third one on going altitude and depth,...........
As you move deeper into the Earth, the value of acceleration due to gravity (g) decreases slightly. This is because the mass directly below you is pulling you down, while the mass above you is also pulling you up. The net effect of these opposing forces is a slight decrease in the value of g as you move deeper into the Earth.
Zero.
If the Earth were to stop rotating, the value of 'g' (acceleration due to gravity) would remain approximately the same at the Earth's surface. The rotation of the Earth does not significantly affect the gravitational pull experienced on the surface.
The weight is due to the force exerted on the body by the gravitational pull by the earth. If no such gravitational pull on the body, then the body becomes weightless. In free space, very far away from the earth the astronauts experience weightlessness. So if M is the mass of the body, then Mg is the weight of the body. Hence weight depends on the value of 'g'. The value of g is the least at the equatorial region. It will be maximum at the poles. As we go at higher altitudes g value decreases. Same way as we go towards the centre of the earth ie as depth increases, g value decreases.
The value of 'g' on Pluto is about 0.063 times the value of 'g' on Earth, which is equivalent to about 0.62 m/s^2. This means that gravity on Pluto is much weaker than on Earth.
9.8 is the value for g, which stands for Gravity.
The value of g would increase if the compound pendulum is taken nearer to the center of the Earth. This is because gravity is stronger closer to the Earth's surface. Conversely, if the compound pendulum is moved further away from the center of the Earth, the value of g would decrease.
The value of the acceleration due to gravity (g) depends on the mass of the Earth and the distance from its center. As an object moves away from Earth, the value of g will decrease because the gravitational force weakens with distance.
I think that g (the gravitational constant) varies dependent on your proximity to other massive bodies. For example the value of g on the moon is less than the value of g on earth. It is not constant throughout the universe.
maybe it is bigger in size than the earth.